Question

我有一个大型数据集，其中包含一列文本，两万行。想要删除该特定列中每行开头的前x个字符（例如3个）。感谢您的协助。

Answer 1

您可以使用gsub函数和简单的正则表达式来做到这一点。这是代码：

# Fake data frame
df <- data.frame(text_col = c("abcd", "abcde", "abcdef"))
df$text_col <- as.character(df$text_col)

# Replace first 3 chracters with empty string ""
df$text_col <- gsub("^.{0,3}", "", df$text_col)

Answer 2

像往常一样。在R中做事的方法很多！

您也可以尝试?substring：

lotsofdata <- data.frame(column.1=c("DataPoint1", "DataPoint2", "DataPoint3", "DataPoint4"),
    +                 column2=c("MoreData1","MoreData2","MoreData3", "MoreData4"),
    +                 stringsAsFactors=FALSE)
> head(lotsofdata)
    column.1   column2
1 DataPoint1 MoreData1
2 DataPoint2 MoreData2
3 DataPoint3 MoreData3
4 DataPoint4 MoreData4

> substring(lotsofdata[,2],4,nchar(lotsofdata[,2]))
[1] "eData1" "eData2" "eData3" "eData4"

或第1列[,1]

> substring(lotsofdata[,1],4,nchar(lotsofdata[,1]))
[1] "aPoint1" "aPoint2" "aPoint3" "aPoint4"

然后将其替换：

x<-substring(lotsofdata[,1],4,nchar(lotsofdata[,1]))

lotsofdata$column.1<-x

> head(lotsofdata)
  column.1   column2
1  aPoint1 MoreData1
2  aPoint2 MoreData2
3  aPoint3 MoreData3
4  aPoint4 MoreData4

Answer 3

使用tidyverse，我们可以使用str_sub（以及一些示例fruit文本字符串）通过直接指定起点和终点来进行此操作：

library(tidyverse)
tbl <- tibble(some_fruit = fruit)
tbl
#> # A tibble: 80 x 1
#>    some_fruit  
#>    <chr>       
#>  1 apple       
#>  2 apricot     
#>  3 avocado     
#>  4 banana      
#>  5 bell pepper 
#>  6 bilberry    
#>  7 blackberry  
#>  8 blackcurrant
#>  9 blood orange
#> 10 blueberry   
#> # … with 70 more rows
tbl %>%
  mutate(chopped_fruit = str_sub(fruit, 4, -1))
#> # A tibble: 80 x 2
#>    some_fruit   chopped_fruit
#>    <chr>        <chr>        
#>  1 apple        le           
#>  2 apricot      icot         
#>  3 avocado      cado         
#>  4 banana       ana          
#>  5 bell pepper  l pepper     
#>  6 bilberry     berry        
#>  7 blackberry   ckberry      
#>  8 blackcurrant ckcurrant    
#>  9 blood orange od orange    
#> 10 blueberry    eberry       
#> # … with 70 more rows

^{由reprex package（v0.2.1）于2019-02-22创建}

如何从R列的每一行中删除前三个字符

3 个答案: