Question

当我用mocha运行单元测试时，我有一个异步函数，我发现它没有存根。我没有看到console.log正在打印登录函数，看起来像是调用了实际的getUser（）函数

// User.js

class User {
  async _getUser(client, email) {
    let result = await new userApi().getUser(new UserInfo(email, email));
    console.log("Get result " + JSON.stringify(result));
    let user = result.users[0];

    console.log("Get User " + JSON.stringify(user));
    return user;
  }
}
module.exports = User;


// Usertest.js

const chai = require("chai");
const sinon = require("sinon");
var chaiAsPromised = require("chai-as-promised");
chai.use(chaiAsPromised).should();
const expect = chai.expect;
const UserInfo = require("../src/model/userInfo");
const User = require("../src/model/user");

describe("Test LogInCommand", function() {
  let user, sandbox;

  beforeEach(() => {
    sandbox = sinon.sandbox.create();
    user = new user();
  });

  afterEach(function afterEach() {
    sandbox.restore();
  });

  it("getUser function", function(done) {
    let User = new UserInfo("email", "email", "station");
    sandbox
      .stub(userApi, "getUser")
      .withArgs(User)
      .returns(
        Promise.resolve({
          users: [
            {
              id: 1
            }
          ]
        })
      );
    sandbox.stub(logger, "info");
    let result = logInCommand._getUser(client, "email", "stationid");
    done();
  });
});

Answer 1

我假设userApi是一个类，因此要进行存根处理，我们必须像下面这样：

sandbox.stub(userApi.prototype, "getUser").withArgs(User)...

我们必须添加prototype来存根类的方法。

我还发现您的测试中有需要解决的问题，这是因为您没有将logInCommand._getUser视为异步调用。因此，这是更新后的代码。

it("getUser function", async function() { // remove `done` and let's use async/await here
  let User = new UserInfo("email", "email", "station");
  sandbox
    .stub(userApi.prototype, "getUser") // add prototype
    .withArgs(User)
    .resolves({ // in new sinon, they have `resolves` method
        users: [
          {
            id: 1
          }
        ]
      });    
  sandbox.stub(logger, "info");
  let result = await logInCommand._getUser(client, "email", "stationid"); // add await because this method is async
  // remove done()
});

希望有帮助

sinon中的异步函数存根调用实际的函数调用

1 个答案: