Question

我正在尝试根据表B中的描述字段更新表A中的税区代码字段。

表B如下。说明是（州-县-市-邮政编码）

Code   Description
10001  TX-Denton-Frisco-75033

表A的每个字段都分开，并且没有郡县字段，我需要根据城市，州和邮政编码来进行最小匹配。

City    State  Post Code
Frisco  TX     75033

在下面的代码中，我仅根据邮政编码进行了匹配，但我需要一种根据城市，州和邮政编码进行匹配的方法。

UPDATE Table A
SET [Tax Area Code] = b.[Code]
FROM Table B AS b
  JOIN Table A AS a 
ON a.[Post Code]=RIGHT(b.[Description],5)

Answer 1

假设数据始终遵循State-county-city-zipcode的格式，并且这些部分都不应丢失，那么您将获得JOIN的信息：

WITH TableB AS(
    SELECT 10001 AS Code,
           'TX-Denton-Frisco-75033' AS [Description]
    UNION ALL
    SELECT 10002 AS Code,
           'MA-Denton-South-Boston-01036' AS [Description]
    UNION ALL
    SELECT 10002 AS Code,
           'FL-Florida-State-Florida-79841' AS [Description]),
TableA AS(
    SELECT 'Frisco' AS City,
           'TX' AS [State],
           75033 AS PostCode
    UNION ALL
    SELECT 'South-Boston' AS City,
           'MA' AS [State],
           01036 AS PostCode
    UNION ALL
    SELECT 'Florida' AS City,
           'FL' AS [State],
           79841 AS PostCode)
SELECT *
FROM TableA A
     LEFT JOIN TableB B ON B.[Description] LIKE CONCAT(A.[state],'-%','-',A.City,'-',RIGHT(CONCAT('00000',A.PostCode),5));

但是效果如何...现在这是一个完全不同的问题（但我建议的不是很好）。

Answer 2

尝试一下，

WITH TableB AS(
    SELECT 10001 AS Code,
           'TX-Denton-Frisco-75033' AS [Description]),
TableA AS(
    SELECT 'Frisco' AS City,
           'TX' AS [State],
           75033 AS PostCode)


SELECT * FROM TableA A
     JOIN TableB B ON 
     a.State=Substring(B.[Description],1, CHARINDEX('-', B.[Description],-1)-1)
     And a.City=Substring (B.[Description],PATINDEX('%' + A.city + '%',B.[Description]) , len(a.city))
     And  a.PostCode=RIGHT(b.[Description],5)

sql根据值的子字符串更新

2 个答案: