Question

我需要为客户货运单据创建一个视图，其中包含下一个信息：好名字，好计数好的价格。

价格可能与一项购买协议不同。对于每个购买协议，可能存在几批装运。 client_shipment_details中的每个商品都可以有序列号，但是client_shipment文档只保留这种商品的总数。这是我的桌子：

purchase_agreement;
+------------------------------+--------------+------+-----+---------+-------- --------+
 | Field                        | Type         | Null | Key | Default | Extra          |
 +------------------------------+--------------+------+-----+---------+----------------+
 | id                           | bigint(20)   | NO   | PRI | NULL    | auto_increment |
 | purchase_agreement_status_id | bigint(20)   | YES  | MUL | NULL    |                   |
+------------------------------+--------------+------+-----+---------+----------------+

purchase_agreement_details;
+-----------------------+------------+------+-----+---------+----------------+
| Field                 | Type       | Null | Key | Default | Extra           |
+-----------------------+------------+------+-----+---------+----------------+
| id                    | bigint(20) | NO   | PRI | NULL    | auto_increment |
| count                 | int(11)    | NO   |     | NULL    |                  |
| price                 | float      | NO   |     | NULL    |                 |
| purchase_agreement_id | bigint(20) | YES  | MUL | NULL    |                 |
| good_id               | bigint(20) | YES  | MUL | NULL    |                |
 +-----------------------+------------+------+-----+---------+----------------+

 goods;
 +-------------+--------------+------+-----+---------+----------------+
 | Field       | Type         | Null | Key | Default | Extra          |
 +-------------+--------------+------+-----+---------+----------------+
 | id          | bigint(20)   | NO   | PRI | NULL    | auto_increment |
 | name        | varchar(255) | YES  |     | NULL    |                |
 +-------------+--------------+------+-----+---------+----------------+


 client_shipment;
 -----------------------+--------------+------+-----+---------+---------------+
 | Field                 | Type         | Null | Key | Default | Extra           |
 +-----------------------+--------------+------+-----+---------+----------------+
 | id                    | bigint(20)   | NO   | PRI | NULL    | auto_increment |
 | jhi_date              | datetime     | YES  |     | NULL    |                  |
 | purchase_agreement_id | bigint(20)   | YES  | MUL | NULL    |                 |
+-----------------------+--------------+------+-----+---------+----------------+


client_shipment_details;
+--------------------+--------------+------+-----+---------+----------------+
| Field              | Type         | Null | Key | Default | Extra          |
+--------------------+--------------+------+-----+---------+----------------+
| id                 | bigint(20)   | NO   | PRI | NULL    | auto_increment |
|
| serial_number      | varchar(255) | YES  |     | NULL    |                |
| client_shipment_id | bigint(20)   | YES  | MUL | NULL    |                |
| good_id            | bigint(20)   | YES  | MUL | NULL    |                |
+--------------------+--------------+------+-----+---------+----------------+

这是我的查询：

SELECT
    temp1.cs_id, temp1.good_id, temp1.count, temp1.price,good.name
FROM
   (
      SELECT csd.cs_id AS cs_id, csd.good_id AS good_id, csd.count AS count, pad.price AS price
      FROM
          (
            SELECT client_shipment_id AS cs_id, good_id, count(*) AS count
            FROM client_shipment_details
            GROUP BY client_shipment_id, good_id
          ) AS csd
      LEFT JOIN
          (
            SELECT pad.good_id AS good_id, pad.price AS price, cs.id AS cs_id
            FROM purchase_agreement_details pad
            JOIN client_shipment cs ON pad.purchase_agreement_id = cs.purchase_agreement_id
          ) AS pad ON csd.good_id = pad.good_id
      GROUP BY cs_id,good_id
  ) AS temp1
JOIN goods ON temp1.good_id = good.id
ORDER BY cs_id,good_id;

一些测试数据：

insert into purchase_agreement values 
(1,1),
(2,1);

insert into purchase_agreement_details values 
(1,2,100,1,1),
(2,4,200,1,2),
(3,6,300,1,3),
(4,7,400,1,4),
(5,3,110,2,1),
(6,8,210,2,2),
(7,4,310,2,3),
(8,5,410,2,4);


insert into goods values 
(1,"desk"),
(2,"sofa"),
(3,"chair"),
(4,"bed");


insert into client_shipment values 
(1,'2019-02-21 09:57:00',1),
(2,'2019-02-21 09:57:00',1),
(3,'2019-02-21 09:57:00',2),
(4,'2019-02-21 09:57:00',2);

insert into client_shipment_details values 
(1,"1-0001",1,1),
(2,"1-0002",1,1),
(3,"2-0001",1,2),
(4,"2-0002",1,2),
(5,"3-0001",1,3),
(6,"3-0002",1,3),
(7,"4-0001",1,4),
(8,"4-0002",1,4),
(9,"1-0003",2,1),
(10,"1-0004",2,1),
(11,"2-0003",2,2),
(12,"2-0004",2,2),
(13,"3-0003",2,3),
(14,"3-0004",2,3),
(15,"4-0003",2,4),
(16,"4-0004",2,4),
(17,"1-0005",3,1),
(18,"1-0006",3,1),
(19,"2-0005",3,2),
(20,"2-0006",3,2),
(21,"3-0005",3,3),
(22,"3-0006",3,3),
(23,"4-0005",3,4),
(24,"4-0006",3,4),
(25,"1-0007",4,1),
(26,"1-0008",4,1),
(27,"2-0007",4,2),
(28,"2-0008",4,2),
(29,"3-0007",4,3),
(30,"3-0008",4,3),
(31,"4-0007",4,4),
(32,"4-0008",4,4);

我想得到这样的结果：

client_shipment_id  good_name   price count

1                   desk        100     2
1                   sofa        200     2                 
1                   chair       300     2
1                   bed         400     2
2                   desk        100     2
2                   sofa        200     2                 
2                   chair       300     2
2                   bed         400     2
3                   desk        110     2
3                   sofa        210     2                 
3                   chair       310     2
3                   bed         410     2
4                   desk        110     2
4                   sofa        210     2                 
4                   chair       310     2
4                   bed         410     2

MySQL数据库：如何为多个表编写SQL

0 个答案: