Question

我有一个模型“ Contact”，其中有许多“ Address”。使用新地址保存联系人时

...
//$contact = some instance of Contact
$contact->addresses()->save(new Address(['street' => '4811 Example Dr.']));

dd($contact->getChanges()); // returns null
// dd($contact->addresses()->getChanges()); // method not available   
// dd($contact->addresses->getChanges()); // method not available

如何查看保存调用后实际进行的更改？

Answer 1

$contact->getChanges()返回null，因为getChanges()试图查看通讯录中是否有任何更改，因此没有。

$contact->addresses()->getChanges()也不起作用，因为$contact->addresses()不返回地址模式的实例。

您可以使用简单的检查save响应进行验证，因为它返回布尔值。

$addressSavedSucccessfully = $contact->addresses()->save(new Address(['street' => '4811 Example Dr.']));

if ($addressSavedSucccessfully) {
    dd('address was saved correctly');
} else {
    dd('something went wrong');
}

我希望能帮上忙。

Answer 2

下面的行返回bolean。您可以检查其返回值。

$value = $contact->addresses()->save(new Address(['street' => '4811 Example Dr.']));


if($value){
   //it is saved
}else{
  //it is not saved    
}

Answer 3

*已编辑试试这个

if (!$contact) {
   $changes = $contact->getChanges();
}

Answer 4

尝试以下操作。对我有用

$this->loadMissing('address');
$address = $this->address;
$address->fill($addressFieldValue);
$address->save();
address->getChanges();

如何在hasMany关系中更改laravel模型？

4 个答案: