无法将反应性强制变为data.frame !!我必须通过单选按钮从用户(数字)中获取数据,并将其放入数据框中以进行新的预测,但是当我尝试形成数据框时会显示错误,请帮忙!!!
图书馆(闪亮)
ui <- fluidPage(
sidebarLayout(
sidebarPanel(
radioButtons(inputId="first", label="a", choices = list("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4),selected = 1),
radioButtons(inputId="second", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="third", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="fourth", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="fifth", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="sixth", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="seventh", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="eighth", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="ninth", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="tenth", label="a", c("None" = 0,"Little" = 1,"Some" = 2,"Much" = 3,"Most" = 4)),
radioButtons(inputId="eleventh", label="a", c("Yes" = 1,"No" = 0)),
radioButtons(inputId="twelfth", label="a", c("Yes" = 1,"No" = 0)),
radioButtons(inputId="thirteenth", label="a", c("Yes" = 1,"No" = 0)),
radioButtons(inputId="fourteenth", label="a", c("Yes" = 1,"No" = 0)),
radioButtons(inputId="fifteenth", label="a", c("Yes" = 1,"No" = 0)),
radioButtons(inputId="sixteenth", label="a", c("Yes" = 1,"No" = 0)),
submitButton("Submit")),
mainPanel(
textOutput("ans")
))
)
server <- function(input, output){
library(caret)
depression_model <- read.csv("C:/Users/Sheikh Afaan/Desktop/Project/web/depression_with_nd_p.csv" , header=TRUE , stringsAsFactors = F)
str(depression_model)
head(depression_model )
set.seed(3233)
intrain <- createDataPartition(y = depression_model$Depression, p= 0.7, list = FALSE)
training <- depression_model[intrain,]
testing <- depression_model[-intrain,]
dim(training)
dim(testing)
anyNA(depression_model)
summary(depression_model)
training[["Depression"]] = factor(training[["Depression"]])
trctrl <- trainControl(method = "repeatedcv", number = 10, repeats = 3)
set.seed(3233)
svm_Linear <- train(Depression ~., data = training, method = "svmLinear",
trControl=trctrl,
preProcess = c("center", "scale"),
tuneLength = 10)
svm_Linear
summary(svm_Linear)
test_pred <- predict(svm_Linear, newdata = testing)
test_pred
tab <- table(Predicted = test_pred, Actual = testing$Depression )
tab
1 - sum(diag(tab))/sum(tab)
#It shows error here please help
new_depression <- reactive({ data.frame("ASadness"=input$first,
"Loconcen"=input$second,
"Asleep"=input$third,
"Aappet"=input$fourth,
"Loenergy"=input$fifth,
"Foguilt"=input$sixth,
"Asbehav"=input$seventh,
"Sthough"=input$eighth,
"Ppains"=input$ninth,
"Eactivity"=input$tenth,
"Wloss"=input$eleventh,
"Ssupport"=input$twelfth,
"Etdsthin"=input$thirteenth,
"Dmaking"=input$fourteenth,
"Fhopilln"=input$fifteenth,
"Addiction"=input$sixteenth)
})
predict(svm_Linear, newdata=new_depression)
output$ans <- renderText({})
}
shinyApp(ui, server)
如何将输入数据放入数据框。感谢所有帮助!
答案 0 :(得分:0)
new_depression
是电抗性导体。您需要此电抗导体返回的值:
predict(svm_Linear, newdata=new_depression())
不是
predict(svm_Linear, newdata=new_depression)
但这在反应性上下文之外是行不通的。因此,您必须执行以下操作:
predictions <- reactive({
predict(svm_Linear, newdata=new_depression())
})
然后通过执行predict(......)
(同样在响应上下文中)获得predictions()
的输出。