Question

我从外部api端点获取以下数组。

输入：-

1. [["date", "country_name", "month"], ["2019-02-21", "US", "Jan"]]
2. ["name", "homeAddress", "zipcode"]

预期输出：-

1. [["Date", "Country Name", "Month"], ["2019-02-21", "US", "Jan"]]
2. ["Name", "Home Address", "Zipcode"]

如何在Ruby on Rails中高效地更改每个数组？

更新：某些名称与预期的有所不同

输入：

["column1", "column2", "date"]

预期输出：

["column3", "column4", "Date"]

如何获得以上输出？

答案：-

输入：-

a=['1', '2', '3', '4']

b= {"1"=>"10", "2"=>"20", "3"=>"30"}

执行：

c=a.map{|i| b[i].nil?? i : b[i] }

输出：-

 ["10", "20", "30", "4"]

Answer 1

您想用空格替换'_'或在字符串中遇到大写字母时带空格

尝试按照以下Rails方法进行操作

"now_isTheTime".titleize.camelize
 => "Now Is The Time"

Answer 2

ar1 = [["date", "country_name", "month"], ["2019-02-21", "US", "Jan"]]
ar2 = ["name", "homeAddress", "zipcode"]


def formatter(string)
 return string if string.length < 3 || string.count("0-9").positive?

 string.titleize.camelize
end

ar1.map{ |sub_arr| sub_arr.map(&method(:formatter)) }
ar2.map(&method(:formatter))

如何以有效的方式更改数组中的值

2 个答案: