Question

我正在做一个简单的问答游戏，在计算结果时遇到了一些麻烦。问题非常简单，我需要找出如何说clicked1的值是否比整个字典中的值大，然后执行此功能。这是字典和我要制作的函数的代码。另外，如果有人可以解释为什么possibilities.value不能解决我的问题，将不胜感激。

var possibilities = {
    'clicked1': 0,
    'clicked2': 0,
    'clicked3': 0,
    'clicked4': 0,
};

function results(){
    if (possibilities['clicked1'] > possibilities){
        console.log("it worked");
    }
};

Answer 1

只需使用Object.values遍历every：

var possibilities = {
    'clicked1': 0,
    'clicked2': 0,
    'clicked3': 0,
    'clicked4': 0,
};

if (Object.values(possibilities).every(val => possibilities.clicked1 >= val || val == possibilities.clicked1)) {
  console.log("It works!");
}

Answer 2

您可以使用every()。您还可以使用Math.max()和Rest参数

检查对象值的最大值。

var ps = {
    'clicked1': 4,
    'clicked2': 1,
    'clicked3': 2,
    'clicked4': 3,
};
if(Object.keys(ps).every(key => ps[key] <= ps.clicked1)){
  console.log("worked")
}
//Second Method:
//Object.values(ps) will return '[4,1,2,3]' And then using ... all values
//are passed to function Math.max() single argument. and it will return the max value out of those and then compare that value with you desired value
if(Math.max(...Object.values(ps)) === ps.clicked1){
    console.log("Worked");
}

Answer 3

这里的方法与您尝试的方法非常相似。

基本上遍历字典中的键和值，而忽略键'clicked1'的值：

let possibilities = {
  'clicked1': 0,
  'clicked2': 0,
  'clicked3': 0,
  'clicked4': 0,
};

function result() {
  for (let key in possibilities) {
    if (key !== 'clicked1' &&  possibilities[key] >= possibilities['clicked1']) {
      return "it did not work";
    }
  }
  return "it worked";
}

console.log(possibilities);
console.log("result() =", result());
possibilities['clicked1'] = 1;
console.log(possibilities);
console.log("result() =", result());

Answer 4

另一种替代方法是检查是否发现某个元素大于possibilities["clicked1"]。如果找到一个，您将知道possibilities["clicked1"]不是最大值，否则它将是最大值。对于此方法，我们可以使用Object.values()从您的对象中获取值的数组，然后我们使用Array.some()进行上述验证：

var possibilities1 = {'clicked1': 6, 'clicked2': 3, 'clicked3': 4, 'clicked4': 5};
var possibilities2 = {'clicked1': 3, 'clicked2': 3, 'clicked3': 4, 'clicked4': 5};

function results(ps)
{
    let found = Object.values(ps).some(x => x > ps['clicked1']);
    found ? console.log("not worked") : console.log("worked");
};

results(possibilities1);
results(possibilities2);

选择整个字典的值

4 个答案: