Question

在循环终止后如何打印频率HashSet？问题似乎在于无法保证循环终止。

use std::collections::HashSet;
use std::fs;

fn main() {
    let f = fs::read_to_string("input.txt").expect("Unable to open file");

    let mut total = 0;
    let mut frequencies = HashSet::new();
    frequencies.insert(0);

    loop {
        for line in f.lines() {
            let line_trimmed = line.trim();
            let something = line_trimmed.parse::<i32>().unwrap();
            total += something;
            // println!("{:?}",total);

            if frequencies.contains(&total) {
                println!("duplicated found {:?}", total);
                return;
            }
            frequencies.insert(total);
        }
    }
    println!("duplicated found {:?}", frequencies);
}

Answer 1

println!("duplicated found {:?}", frequencies);无法访问，因为在调用return时，您正在返回main函数。

将循环更改为while，并设置一个变量以退出while循环。

let mut duplicated_found = false;
while !duplicated_found {
    for line in f.lines() {

        let line_trimmed = line.trim();
        let something = line_trimmed.parse::<i32>().unwrap();
        total += something;
        // println!("{:?}",total);

        if frequencies.contains(&total) {
            println!("duplicated found {:?}", total);
            duplicated_found = true;
            break; // This breaks out of the for loop
        }
        frequencies.insert(total);
    }
}
println!("duplicated found {:?}", frequencies);

或者您可以使用标签指定要突破的循环：

'outer: loop {
    for line in f.lines() {

        let line_trimmed = line.trim();
        let something = line_trimmed.parse::<i32>().unwrap();
        total += something;
        // println!("{:?}",total);

        if frequencies.contains(&total) {
            println!("duplicated found {:?}", total);
            break 'outer; // This breaks out of the outer loop
        }
        frequencies.insert(total);
    }
}
println!("duplicated found {:?}", frequencies);

println！循环外是无法访问的语句，如何以“可访问”的方式使用println

1 个答案: