Question

场景：我有一张桌子返回无法出售我的水果的市场。最多有4种不同的条件将水果排除在市场之外。

我的代码是：

SELECT DISTINCT RPin, Variety, SubDivisionId, BlockId
, STUFF((
    SELECT ',' + CAST(ClearanceID as varchar)
    FROM [RPin_ExclusionT] t1
    where t1.RPin = t2.RPin AND t1.Variety = t2.Variety AND t1.SubDivisionId = t2.SubDivisionId AND t1.BlockId = t2.BlockId
    order by t1.ClearanceID 
    FOR XML PATH('')
), 1, 1, '') AS Clearance
FROM [RPin_ExclusionT] t2

例如：

Rpin   Variety   Subdivision   Block   Clearance
1234   039       B             A       RUS
1234   039       B             A       CHN

会导致：

Rpin   Variety   Subdivision   Block   Clearance
1234   039       B             A       RUS, CHN

如果每个字段都有数据，我的代码就可以工作。有时候，间隙可能只有一个RPin，其他所有内容都为NULL

Rpin   Variety   Subdivision   Block   Clearance
1234   039       B             A       RUS
1234   039       B             A       CHN
1234   NULL      NULL          NULL    JAP
1234   NULL      NULL          NULL    TWN

我是要返回与以前相同的结果

Rpin   Variety   Subdivision   Block   Clearance
1234   039       B             A       RUS, CHN
1234   NULL      NULL          NULL    JAP, TWN

但是，任何地方任何列中都有NULL值都会导致我的清除列中有NULL值。

Rpin   Variety   Subdivision   Block   Clearance
1234   039       B             A       RUS, CHN
1234   NULL      NULL          NULL    NULL

我充其量只是SQL的中级课程，不能完全像上面那样调整查询条件……任何指针将不胜感激。

Answer 1

我更喜欢在子查询之前执行.navbar>.container-fluid { display: block; padding-right: 0px; } nav.navbar .collapse { display: inline-block; font-size: 1.2em; position: relative; top: -140px; float: right; margin: 15px 15px 8px 0; /*padding: 10px;*/ background-color: transparent; background-image: none; border: 1px solid transparent; border-radius: 4px; -moz-box-shadow: none; -webkit-box-shadow: none; box-shadow: none; overflow-x: visible; padding-right: 15px; padding-left: 15px; padding-bottom: 10px; border-top: none; -webkit-overflow-scrolling: touch; } .menu-main-menu-container { position: relative; right: 80px; }。您需要distinct安全的比较：

NULL

Answer 2

假设所有字段都是varchars-请尝试以下操作：

SELECT DISTINCT RPin, Variety, SubDivisionId, BlockId
    ,STUFF((
        SELECT ',' + CAST(ClearanceID AS VARCHAR(8000))
        FROM [RPin_ExclusionT] t1
        WHERE COALESCE(t1.RPin,'') = COALESCE(t2.RPin,'')
            AND COALESCE(t1.Variety,'') = COALESCE(t2.Variety,'')
            AND COALESCE(t1.SubDivisionId,'') = COALESCE(t2.SubDivisionId,'')
            AND COALESCE(t1.BlockId,'') = COALESCE(t2.BlockId,'')
        ORDER BY t1.ClearanceID 
        FOR XML PATH('')
    ), 1, 1, '') AS [Clearance]
FROM [RPin_ExclusionT] t2

将结果与一些空值连接

2 个答案: