Question

我有三个实体，一个存储库扩展了CrudRepository，我想进行下一个查询，但是我不能。我上半身或附近有语法错误。我认为问题出在查询中使用了多个表，并且/或者我没有在实体中使用任何标签或声明。

import java.util.List;
import org.springframework.data.jpa.repository.Query;
import org.springframework.data.repository.CrudRepository;
import org.springframework.data.repository.query.Param;
import com.companyname.springapp.business.entities.TableA;

public interface TableARepository extends CrudRepository<TableA, Integer>{

@Query(value = "SELECT DISTINCT a.*"
            +"FROM TableB AS b, TableA_TableB AS ab, TableA AS a"
            +"WHERE upper(b.nick_name) like upper(concat('%',:name,'%'))"
            +"AND b.nick_name_id=ab.nick_name_id"
            +"AND ab.id=a.id", 
              nativeQuery = true)
            List<tableA> test(
              @Param("name") String name);

我的实体：

TableA

import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

import com.companyname.springapp.web.Views;
import com.fasterxml.jackson.annotation.JsonView;


@Entity
@Table(name="TableA")
public class TableA{

    @Id
    @JsonView(Views.Public.class)
    private Integer id;

    //more columns, constructs and getters and setters

TableB

    //... imports
    @Entity
    @Table(name="TableB")
    public class TableB{

    @Id
    @JsonView(Views.Public.class)
    private Integer nick_name_id;

    @JsonView(Views.Public.class)
    private String nick_name;

    //more columns, constructs and getters and setters

TableA_TableB

    //... imports
    @Entity
    @Table(name="TableA_TableB")
    public class TableA_TableB{

    @Id
    @JsonView(Views.Public.class)
    private Integer id;

    @JsonView(Views.Public.class)
    private Integer nick_name_id;

    //more columns, constructs and getters and setters

我有TableAManager

import java.util.List;

import com.companyname.springapp.business.entities.TableA;

public interface TableAManager {

    public List<TableA> test(String name);
}

实现JPATableAManager

import java.util.ArrayList;
import java.util.List;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;

import com.companyname.springapp.business.entities.TableA;
import com.companyname.springapp.business.repositories.TableARepository;

@Service
public class JPATableAManager implements TableAManager {

    @Autowired
    private TableARepository tableARepository;

    public List<TableA> getTableA() {
        return (List<TableA>) tableARepository.test();
    }

PD：请问我的英语

Answer 1

您的SQL语句缺少空格。

"SELECT DISTINCT a.*"
+"FROM TableB AS b, TableA_TableB AS ab, TableA AS a"
+"WHERE upper(b.nick_name) like upper(concat('%',:name,'%'))"
+"AND b.nick_name_id=ab.nick_name_id"
+"AND ab.id=a.id"

串联时 "SELECT DISTINCT a.*FROM TableB AS b, TableA_TableB AS ab, TableA AS aWHERE upper(b.nick_name) like upper(concat('%',:name,'%'))AND b.nick_name_id=ab.nick_name_idAND ab.id=a.id"

这导致aWhere成为TableA的别名，而where子句没有被解析。

以这种方式构造SQL语句时，每行以空格结尾：

"SELECT DISTINCT a.* "
+"FROM TableB AS b, TableA_TableB AS ab, TableA AS a "
+"WHERE upper(b.nick_name) like upper(concat('%',:name,'%')) "
+"AND b.nick_name_id=ab.nick_name_id "
+"AND ab.id=a.id"

如何使用Spring CrudRepository进行自定义查询将两个或多个实体与存储库一起使用

1 个答案: