如何摆脱相同计数在MySQL中的冲突

Question

1
    select h.hacker_id,h.name ,count(*) as cc from hackers h
    inner join challenges s
    on h.hacker_id=s.hacker_id
    group by h.hacker_id,h.name
    having  cc=(select  count(*) from challenges c
    group by c.hacker_id
    order by count(*) desc
    limit 1
                )
    or
    cc in
    (
       select total from (select count(*) as total from challenges c 
                               group by c.hacker_id
                              )counts
        group by total
        having count(*)=1

        )

        order by cc desc ,hacker_id asc



2
    select h.hacker_id,h.name ,count(*) as cc from hackers h
    inner join challenges s
    on h.hacker_id=s.hacker_id
    group by h.hacker_id,h.name
    having  cc=(select  count(*) from challenges c
    group by c.hacker_id
    order by count(*) desc
    limit 1
                )
    or
    count(*) in
    (
       select total from (select count(*) as total from challenges c 
                               group by c.hacker_id
                              )counts
        group by total
        having count(*)=1

        )

        order by cc desc ,hacker_id asc

在我写cc而不是计数的第一个中它起作用 但是在第二次查询中，子查询不能给出正确的结果。它不与计数一起使用。 我不知道为什么mysql表现出这种方式 两个查询在ms sql server中都能正常工作 但是在mysql中有一个我讨论过的问题