如下所示,使用JPA查询从数据库中检索UserRequest
对象。
@Query("SELECT req.supervisorEmail from User u, UserRequest as req WHERE u.username = req.userRequestName and req.userRequestRole= '4' and u.active=true")
public List<UserRequest> getSupervisorEmailIds();
具有UserRequest
POJO类,如下所示。
public class UserRequest implements Identifiable<Long>, LazilyLoadable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@JsonIgnore
private Long id;
@Column(name = "supervisor_email")
private String supervisorEmail;
@Column(name="user_request_name")
private String userRequestName;
@Column(name="user_request_role")
private String userRequestRole;
}
当尝试遍历UserRequest
对象时,获得以下代码的ClassCastException
。
List<UserRequest> supervisorEmailIds = userService.getSupervisorEmailIds();
for(UserRequest s: supervisorEmailIds) { // throwing exception on this line.
if(s!=null) {
System.out.println("Printing -->"+s.getSupervisorEmail());
}
System.out.println("Null error");
}
以下是错误消息。
2019-02-22 00:34:26,719 [http-9191-1] ERROR com.cat.pscs.api.controller.BaseController: 83 - Unhandled exception while processing request for URL : http://localhost:9191/security/users/get-supervisor-emailids with exception : java.lang.String cannot be cast to com.cat.pscs.security.model.UserRequest
java.lang.ClassCastException:无法将java.lang.String强制转换为com.cat.pscs.security.model.UserRequest 在com.cat.pscs.security.controller.UserController.getSupervisorEmailIds(UserController.java:320)
答案 0 :(得分:2)
您确定下面的行返回UserRequestList吗?我认为它会返回字符串列表
List<UserRequest> supervisorEmailIds = userService.getSupervisorEmailIds();
只需更改返回UserRequest对象列表的sql查询即可。
答案 1 :(得分:2)
您的查询将返回String
的列表,而您希望获得UserRequest
的列表。如下更改查询应该可以完成这项工作:
@Query("SELECT req from User u, UserRequest as req WHERE u.username = req.userRequestName and req.userRequestRole= '4' and u.active=true")
答案 2 :(得分:1)
您在@Query
里面写过
SELECT req.supervisorEmail from User u, UserRequest as req...
我假设supervisorEmail
是VARCHAR
或CHAR
表列。
您只提取了一个String
列。
如果您需要UserRequest
,则需要
SELECT req from User u, UserRequest as req...