当前,该程序将运行一列URL,并将所选数据输出到相邻的单元格。我可以设置它从哪一列开始,但这就是我所能做的。现在,我只将其工作在一个专栏中。我如何指示它说第4列(E列),并在到达第0列(A)时自上而下地工作?然后也许是另一个,然后说J列?
我相信我的问题出在“ while(!(cell = sheet.getCell ...”)行之内,但是我不确定在不更改程序的情况下在此处进行更改。
我的代码如下:
> testif <- function(x) {
+ if (any(is.na(x))) {
+ paste(na.locf(x), letters, sep = "")
+ }
+ }
for (x in df$b) {
+ if (any(is.na(x))) {
+ paste(test$b, na.locf(x), letters, sep = "")
+ }
+ }
答案 0 :(得分:0)
为简化代码,我假设价格始终位于下一列(+1)。
也可以处理几列而不是使用单个值int URL_COLUMN = 0
,我将其替换为要处理的列数组:int[] URL_COLUMNS = { 0, 4, 9 }; // Columns A, E, J
。
然后,您可以遍历每列{0, 4, 9}
并将数据保存到下一列{1, 5, 10}
。
private static final int[] URL_COLUMNS = { 0, 4, 9 }; // Columns A, E, J
public static void main(final String[] args) throws Exception {
Workbook originalWorkbook = Workbook.getWorkbook(new File("C:/Users/Shadow/Desktop/original.xls"));
WritableWorkbook workbook = Workbook.createWorkbook(new File("C:/Users/Shadow/Desktop/updated.xls"), originalWorkbook);
originalWorkbook.close();
WritableSheet sheet = workbook.getSheet(0);
Cell cell;
// loop over every column
for (int i = 0; i < URL_COLUMNS.length; i++) {
int currentRow = 1;
while (!(cell = sheet.getCell(URL_COLUMNS[i], currentRow)).getType().equals(CellType.EMPTY)) {
String url = cell.getContents();
System.out.println("Checking URL: " + url);
if (url.contains("scrapingsite1.com")) {
String Price = ScrapingSite1(url);
System.out.println("Scraping Site1's Price: " + Price);
// save price into the next column
Label cellWithPrice = new Label(URL_COLUMNS[i] + 1, currentRow, Price);
sheet.addCell(cellWithPrice);
}
currentRow++;
}
}
workbook.write();
workbook.close();
}