Question

我有一个名为Array1的数组。其中包含诸如Array1 =“ John，Ali，Ali，Mark，Susan，Susan，Susan，Susan，Ali，Julie，John”之类的名称。

我想： 1st-计算每个名称在Array1中出现多少次 2-创建一个单独的数组，从Array1中删除重复项第3个-将第二个重复计数添加到第二个数组。

因此，我的最终数组将如下所示：

Array2 =
John => 2
Ali => 3
Mark => 1
Susan => 3
Julie =>1

我将如何处理？在正确方向上的任何指针将不胜感激。谢谢

Answer 1

<?php
$array1 = ["John", "Ali", "Ali", "Mark", "Susan", "Susan", "Susan", "Ali", "Julie","John"];
print_r(array_count_values($array1));
?>

输出

Array ( [John] => 2 [Ali] => 3 [Mark] => 1 [Susan] => 3 [Julie] => 1 )

Answer 2

您可以使用PHP的内置功能来实现所有这些功能：

https://3v4l.org/OHgPv

$array = ['Susan', 'Mark', 'Susan', 'Stephan'];

计算每个名称在Array1中出现的次数

$valuesCounted = array_count_values($array);

创建一个单独的数组，从Array1中删除重复项

$unique = array_unique($array);

将重复计数添加到第二个数组。

$duplicates = array_filter($valuesCounted, function($var) {
    return $var > 1;
});

$final = $unique;
$final['duplicates'] = $duplicates;

将它们放在一起：

<?php

$array = ['Susan', 'Mark', 'Susan', 'Stephan'];

$valuesCounted = array_count_values($array);


$unique = array_unique($array);

$duplicates = array_filter($valuesCounted, function($var) {
    return $var > 1; // We only want to have values in our array where the value was found more than once i.e. is a duplicate.
});

$final = $unique;
$final['duplicates'] = $duplicates;

var_dump($final);

7.1.25-7.3.2的输出

array（4）{ [0] => 字符串（5）“ Susan” [1] => 字符串（4）“标记” [3] => string（7）“斯蒂芬” [“重复项”] => array（1）{ [“ Susan”] => 整数（2） } }

参考文献：

http://php.net/manual/en/function.array-count-values.php

http://php.net/manual/en/function.array-unique.php

http://php.net/manual/en/function.array-filter.php

Answer 3

export function fetchPost(postId){ const request = axios.get(`${ROOT_URL}/posts${postId}`); return { type: FETCH_POST, payload: request }; }进行营救：）

import { FETCH_POST } from "../actions";

export default function(state = {id: 0, title: "", infos: [{id: 0, content: "", authorId: 0}]}, action){
switch(action.type){
    case FETCH_POST:
        return action.payload;
  }

return state;
}

Answer 4

以上所有问题的完整说明

 <?php
$testArray = [
    'foo',
    'bar',
    'beer',
    'coffee',
    'foo',
    'bar',
    'beer',
    'coffee',
    'foo',
    'bar',
    'beer',
    'coffee',
];


$countArray = count($testArray);

$duplicatesRemoved = array_unique($testArray);
$vals = array_count_values($testArray);

print_r($vals);

Answer 5

检查array_count_value函数。它将非常适合您。检查以下代码：

$collection = array("Geeks", "for", "Geeks", "Geeks", "Welcome", "for");

$collectionValCounter = array_count_values($collection); // This will print all values with their apperance counter.

$collectionUnique = array_values(array_flip($collectionValCounter)); //Unique values with reset keys.
print_r($collectionValCounter); 
print_r($collectionUnique);

希望它对您有帮助。

Answer 6

这样的事情会做我想做的事情：

$array2 = array();
foreach {$array1 as $name}{
    if (array_key_exists($name, $array2)) {
        $array2[$name] = $array2[$name] + 1;
    } else {
        $array2[$name] = 1;
    }
}

问候，凯

Answer 7

只需使用内置的PHP函数

array_count_values()

例如

$array1 = array('john','john', 'Ali');


$array2 = array_count_values($array);


print_r($array2);

结果：

Array ( [john] => 2 [Ali] => 1 )

通过计算重复的php，从两个单独的数组创建新数组

7 个答案: