Question

我正在尝试将新值插入Firebase实时数据库。但是每次我“注册”新用户时，我的数据库数据都会被新用户替换。我对如何做到这一点完全感到困惑。

这是我的代码。

//Create a new user with txtfield email & password
     Auth.auth().createUser(withEmail: email, password: password) { authResult, error in

     //Printing error if any
     if error != nil
     {
     print(error as Any)
     return
     }

     //Getting database reference
     let ref = Database.database().reference()

     //Values to insert into database
        let values = ["Username": self.username, "Email": self.email, "Name1": self.name1, "Name2": self.name2, "Name3": self.name3, "Name4": self.name4, "Name5": self.name5, "Name6": self.name6, "Dog1": dog1, "Dog2": dog2, "Dog3": dog3]

     //Updating the child values
     ref.updateChildValues(values, withCompletionBlock: { (err, ref) in


     //Printing error if any
     if err != nil
     {
     print(err as Any)
     return
     }

     //Succeded if no errors
     print("Saved user successfully in Firebase database!")

     })

我认为问题出在

         ref.updateChildValues(values, withCompletionBlock: { (err, ref) in

但是我不知道该如何替换。因此，简而言之。每次创建新用户时，数据库数据都会被替换。我基本上希望它为每个用户创建一个新的“行”。

Answer 1

您需要将项目插入像users/userID这样的孩子下

 guard let firUser = authResult.user else { return }
 let userID = firUser.uid
 let ref = Database.database().reference()
 let user = ref.child("users/\(userID)")
 user.updateChildValues////

数据库

  > users

    > njfjnjnf889489489 // some user uid

      > name

      > mail

    > 322jnjnf889489483 // some user uid

      > name

      > mail

在Firebase中插入而不是更新

1 个答案: