从电子表格导入数据时遇到问题。 我正在尝试创建包含所有数据的列表。但是只有最后一行添加到列表中。
from openpyxl import load_workbook
path = "excel.xlsx"
l_data = load_workbook(path)
sheet = l_data.active
c_row = sheet.max_row
c_column = sheet.max_column
out_data=[]
dict={}
for a in range(1, c_row + 1):
for b in range(1, c_column + 1):
ob = sheet.cell(row=a, column=b)
dict[b] = ob.value
out_data.append(dict)
我需要这样的输出数据: [{1:“ row1_call1”,2:“ row1_call2”},{1:“ row2_call1”,2:“ row2_call2”}]
答案 0 :(得分:0)
尝试一个:
<?php
namespace App\Security;
use App\Entity\User;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\Exception\CustomUserMessageAuthenticationException;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Symfony\Component\Security\Core\Exception\InvalidCsrfTokenException;
use Symfony\Component\Security\Core\Security;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Csrf\CsrfToken;
use Symfony\Component\Security\Csrf\CsrfTokenManagerInterface;
use Symfony\Component\Security\Guard\Authenticator\AbstractFormLoginAuthenticator;
use Symfony\Component\Security\Http\Util\TargetPathTrait;
class LoginAuthFormAuthenticator extends AbstractFormLoginAuthenticator
{
use TargetPathTrait;
private $entityManager;
private $urlGenerator;
private $csrfTokenManager;
private $passwordEncoder;
public function __construct(EntityManagerInterface $entityManager, UrlGeneratorInterface $urlGenerator, CsrfTokenManagerInterface $csrfTokenManager, UserPasswordEncoderInterface $passwordEncoder)
{
$this->entityManager = $entityManager;
$this->urlGenerator = $urlGenerator;
$this->csrfTokenManager = $csrfTokenManager;
$this->passwordEncoder = $passwordEncoder;
}
public function supports(Request $request)
{
return 'app_login' === $request->attributes->get('_route')
&& $request->isMethod('POST');
}
public function getCredentials(Request $request)
{
$credentials = [
'email' => $request->request->get('email'),
'password' => $request->request->get('password'),
'csrf_token' => $request->request->get('_csrf_token'),
];
$request->getSession()->set(
Security::LAST_USERNAME,
$credentials['email']
);
return $credentials;
}
public function getUser($credentials, UserProviderInterface $userProvider)
{
$token = new CsrfToken('authenticate', $credentials['csrf_token']);
if (!$this->csrfTokenManager->isTokenValid($token)) {
throw new InvalidCsrfTokenException();
}
$user = $this->entityManager->getRepository(User::class)->findOneBy(['email' => $credentials['email']]);
if (!$user) {
// fail authentication with a custom error
throw new CustomUserMessageAuthenticationException('Email could not be found.');
}
return $user;
}
public function checkCredentials($credentials, UserInterface $user)
{
return $this->passwordEncoder->isPasswordValid($user, $credentials['password']);
}
public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey)
{
if ($targetPath = $this->getTargetPath($request->getSession(), $providerKey)) {
return new RedirectResponse($targetPath);
}
// For example : return new RedirectResponse($this->urlGenerator->generate('some_route'));
return new RedirectResponse($this->urlGenerator->generate('page_forum'));
}
protected function getLoginUrl()
{
return $this->urlGenerator->generate('app_login');
}
}
它更改字典值的类型。因此,仅此行更改自:
from openpyxl import load_workbook
path = "excel.xlsx"
l_data = load_workbook(path)
sheet = l_data.active
c_row = sheet.max_row
c_column = sheet.max_column
out_data=[]
dict={}
for a in range(1, c_row + 1):
for b in range(1, c_column + 1):
ob = sheet.cell(row=a, column=b)
dict[b] = ob.value
out_data.append(str(dict))
print(out_data)
收件人:
out_data.append(dict)
如果您想了解更多将字典追加到列表的信息,请检查该站点: python: Appending a dictionary to a list - I see a pointer like behavior
所以这也起作用:
out_data.append(str(dict))