减少重复的代码,尝试将函数分配给变量-不起作用

时间:2019-02-21 08:58:56

标签: javascript function dry

为了减少重复的代码,我试图创建一个if语句来为变量分配一个函数或另一个函数,但这没有用!?

我试图做的是

const graphCall = (params['sfid'] === 'potential_engagements') ?  this.engagementService.potentialsGraph() : this.engagementService.graph()

该语法本身不会引发错误,但是当我尝试使用时会

graphCall.then(animate => 

...不起作用! 我是否缺少某些东西,是否可以不分配功能,是否有另一种相似或不同的方式来检查和删除重复的代码?

我的代码:

if (params['sfid'] === 'potential_engagements') {
    this.engagementService.potentialEngagements = true;
    this.engagementService
      .potentialsGraph()
      .then(animate => {
        this.graph = new EngagementGraph(d3.select('.Engagement-GraphSVG'));
        this.track();
        this.engagementService.isGraph = true;
        this.engagementService
          .getAllProducts()
          .then(() => this.downloading = false)
          .catch(err => this.pdfError = true)
        this.findForumContact();
        this.updateDateLabel();
        this.addMemberPicture();
        this.setup(animate);
      })
      .catch(error => this.handleError(error));
} else {
    this.engagementService
      .graph(params['sfid'])
      .then(animate => {
        this.graph = new EngagementGraph(d3.select('.Engagement-GraphSVG'));
        this.track();
        this.engagementService.isGraph = true;
        this.engagementService
          .getAllProducts()
          .then(() => this.downloading = false)
          .catch(err => this.pdfError = true)
        this.findForumContact();
        this.updateDateLabel();
        this.addMemberPicture();
        this.setup(animate);
      })
      .catch(error => this.handleError(error));
}

谢谢您的帮助!

2 个答案:

答案 0 :(得分:1)

potential_engagements块有两个其他块没有的东西:

this.engagementService.potentialEngagements = true; <------
this.engagementService
  .potentialsGraph() <------
  .then(animate => {

另一块只有另一块没有的东西:

this.engagementService
  .graph(params['sfid']) <------
  .then(animate => {

.then(animate及其后的所有内容都是相同的,所以我建议将所有内容抽象为一个函数,也许称为handleGraphProm

const handleGraphProm = prom => prom.then(animate => {
  this.graph = new EngagementGraph(d3.select('.Engagement-GraphSVG'));
  this.track();
  this.engagementService.isGraph = true;
  this.engagementService
    .getAllProducts()
    .then(() => this.downloading = false)
    .catch(err => this.pdfError = true)
  this.findForumContact();
  this.updateDateLabel();
  this.addMemberPicture();
  this.setup(animate);
})
.catch(error => this.handleError(error));

并调用:

if (params['sfid'] === 'potential_engagements') {
  this.engagementService.potentialEngagements = true;
  handleGraphProm(this.engagementService.potentialsGraph());
} else {
  handleGraphProm(this.engagementService..graph(params['sfid']));
}

答案 1 :(得分:1)

它不起作用的原因可能是因为您还有一个附加的this.engagementService.potentialEngagements = true,该附加值未在三元运算中分配。将thenablepotentialsGraph返回的graph放入变量。然后在其上调用then

let graphCall;

if (params['sfid'] === 'potential_engagements') {
  this.engagementService.potentialEngagements = true;
  graphCall = this.engagementService.potentialsGraph()
} else {
  graphCall = this.engagementService.graph(params['sfid'])
}

graphCall.then(animate => {
    this.graph = new EngagementGraph(d3.select('.Engagement-GraphSVG'));
    this.track();
    this.engagementService.isGraph = true;
    this.engagementService
      .getAllProducts()
      .then(() => this.downloading = false)
      .catch(err => this.pdfError = true)
    this.findForumContact();
    this.updateDateLabel();
    this.addMemberPicture();
    this.setup(animate);
  })
  .catch(error => this.handleError(error));