Question

如何导入具有绝对路径的模块并将参数传递给该模块，以便被调用的模块可以实际在其内部使用该变量？绝对路径是指这样的"/home/example.com/directory/file.py"。我将此模块名称作为实际脚本的命令行参数的一部分。在该脚本中，我必须导入file.py并将某些参数传递给它们。防爆码：

    filename = '/home/example.com/directories/file.py'
    path = re.split(filename, script_path, maxsplit=1)[0]
    print(path) --> /home/example.py/directories/
    module_name = filename.rstrip('.py')
    print(module_name) --> file.py
    spec = importlib.util.spec_from_file_location(module_name, path)
    module = importlib.util.module_from_spec(spec)
    print(type(module))
    # filepath = re.sub('/','.',script_path)
    # print(filepath)
    # module = importlib.import_module(script_path)
    module.testvars = [r_config, t_config]
    # spec.loader.exec_module(module)
    alltest = unittest.TestSuite()
    alltest.addTest(unittest.findTestCases(module))
    runner = unittest.TextTestRunner()

但是此代码出现以下错误：

Traceback (most recent call last):                                                            module = importlib.util.module_from_spec(spec)
  File "<frozen importlib._bootstrap>", line 568, in module_from_spec
AttributeError: 'NoneType' object has no attribute 'loader'

导入具有绝对路径的python模块会引发错误

0 个答案: