Question

我正在编码一个对消息进行编码的程序。输出应通过写下正整数N和符号来编码消息。您可以通过在一行上连续写N次该符号来解码该消息。我的IDE中出现“无此类元素异常”错误。

 import java.util.;
 import java.io.;

 public class Main
 {
     public static void main (String args[]) throws IOException
     {
         new Main ();
     }
     public Main () throws IOException
     { 
         Scanner reader = new Scanner(System.in);  // Reading from System.in
         BufferedReader in = new BufferedReader (new InputStreamReader (System.in));

         int l = reader.nextInt(); //number of lines
         int times [] = new int [l];
         String string [] = new String [l];

         for (int i = 0; i < l; i++) {
             StringTokenizer st = new StringTokenizer(in.readLine());

             String n = st.nextToken(); // <-- error occurs here
             String n2 = st.nextToken();

             int n1 = Integer.parseInt(n);

             times[i] = n1;
             string[i] = n2;
         }
         for (int i = 0; i < l; i++) {

             function(times[i], string[i]);

             if (i != (l-1))
                 System.out.println();
         }
     }

     public void function (int a, String b) {
         for (int i = 0; i < a; i++) {
             System.out.print(b);
         }
     }
 }

Answer 1

问题出在这方面：

StringTokenizer st = new StringTokenizer(in.readLine());

         String n = st.nextToken(); // <-- error occurs here
         String n2 = st.nextToken();

         int n1 = Integer.parseInt(n);

         times[i] = n1;
         string[i] = n2;

一种方法是这样做：

for (int i = 0; i < l; i++) {
         String line = in.readLine();
         String[] splitLine = line.split(" ");

        int n1 = Integer.parseInt(splitLine[0]);
        String n2 = splitLine[1];

         times[i] = n1;
         string[i] = n2;
}

无此类元素异常/字符串分词器错误

1 个答案: