import pprint
def mult_matrix(M, N):
"""Multiply square matrices of same dimension M and N"""
# Converts N into a list of tuples of columns
tuple_N = zip(*N)
# Nested list comprehension to calculate matrix multiplication
return [[sum(el_m * el_n for el_m, el_n in zip(row_m, col_n)) for col_n in tuple_N] for row_m in M]
def pivot_matrix(M):
"""Returns the pivoting matrix for M, used in Doolittle's method."""
m = len(M)
# Create an identity matrix, with floating point values
id_mat = [[float(i ==j) for i in range(m)] for j in range(m)]
# Rearrange the identity matrix such that the largest element of
# each column of M is placed on the diagonal of of M
for j in range(m):
row = max(range(j, m), key=lambda i: abs(M[i][j]))
if j != row:
# Swap the rows
id_mat[j], id_mat[row] = id_mat[row], id_mat[j]
return id_mat
def lu_decomposition(A):
"""Performs an LU Decomposition of A (which must be square)
into PA = LU. The function returns P, L and U."""
n = len(A)
# Create zero matrices for L and U
L = [[0.0] * n for i in range(0,n)]
U = [[0.0] * n for i in range(0,n)]
# Create the pivot matrix P and the multipled matrix PA
P = pivot_matrix(A)
PA = mult_matrix(P, A)
# Perform the LU Decomposition
for j in range(n):
# All diagonal entries of L are set to unity
L[j][j] = 1.0
# LaTeX: u_{ij} = a_{ij} - \sum_{k=1}^{i-1} u_{kj} l_{ik}
for i in range(j+1):
s1 = sum(U[k][j] * L[i][k] for k in range(i))
U[i][j] = PA[i][j] - s1
# LaTeX: l_{ij} = \frac{1}{u_{jj}} (a_{ij} - \sum_{k=1}^{j-1} u_{kj} l_{ik} )
for i in range(j, n):
s2 = sum(U[k][j] * L[i][k] for k in range(j))
L[i][j] = (PA[i][j] - s2) / U[j][j]
return (P, L, U)
A = [[7, 3, -1, 2], [3, 8, 1, -4], [-1, 1, 4, -1], [2, -4, -1, 6]]
P, L, U = lu_decomposition(A)
print ("A:")
pprint.pprint(A)
print ("P:")
pprint.pprint(P)
print ("L:")
pprint.pprint(L)
print ("U:")
pprint.pprint(U)
答案 0 :(得分:0)
我相信错误在于以下for循环
for i in range(j+1):
s1 = sum(U[k][j] * L[i][k] for k in range(i))
U[i][j] = PA[i][j] - s1
当for j in range(n):
时第一个循环从(j==n
)开始,第二个循环进行到n+1
,从而引发异常。希望对您有帮助