我正在创建一个带有语音输入的简单披萨应用程序。 在创建这篇文章之前,我进行了很多搜索,没有发现有用的东西。
小提琴无法正确运行代码,因此请不要在那儿运行。
问题:
当我尝试在我的“输入” 中使用“命令” 时(例如
count = 0
def talkToMe(audio):
global count
print(audio)
text_to_speech = gTTS(text=audio, lang='en-us')
text_to_speech.save(f'speech{count%2}.mp3')
mixer.init()
mixer.music.load(f'speech{count%2}.mp3')
mixer.music.play()
count += 1
def myCommand():
r = sr.Recognizer()
with sr.Microphone() as source:
print('Ready...')
r.pause_threshold = 1
r.adjust_for_ambient_noise(source, duration=1)
audio = r.listen(source)
try:
command = r.recognize_google(audio).lower()
print('You said: ' + command + '\n')
#loop back to continue to listen for commands if unrecognizable speech is received
except sr.UnknownValueError:
print('Your last command couldn\'t be heard')
command = myCommand();
return command
def assistant(command):
def pick_or_deli():
global delivery
global customer_name
global customer_telephone
delivery = input("pickup - pick up / delivery - delivery:" + command)
delivery = delivery.upper()
if delivery == "DELIVERY":
while running == True:
..............................
我只是得到:
不要为小写的“交付”花钱。 即使我更改此行:
if delivery == "DELIVERY":
对此:
if delivery == "delivery":
它不起作用。即使我按Enter。系统无法将其识别为输入。
任何解决方案/建议都很好。