Question

我有此列表：

mylist = ['*', 'Drama', 'Film Noir', 'Mystery', 'Romance', '*', 'Dance', 'Drama', 'Musical', '*', 'Crime', 'Drama', '*', 'Action', 'Drama', 'Period', 'Western', '*', 'Adaptation', 'Based-on', 'Comedy', 'Romance', '*', 'Mystery', 'Thriller', '*', 'Comedy']

很明显，元素'*'分隔列表中的组。如何在'*'之间对元素的出现进行分组？所需的结果将如下所示：

expected_list = [('Drama', 'Film Noir', 'Mystery', 'Romance'), ('Dance', 'Drama', 'Musical'), ('Crime', 'Drama'), ('Action', 'Drama', 'Period', 'Western'), ('Adaptation', 'Based-on', 'Comedy', 'Romance'), ('Mystery', 'Thriller'), ('Comedy')]

Answer 1

这是经典的use case for itertools.groupby：

from itertools import groupby

expected_list = [tuple(grp) for isstar, grp in groupby(mylist, key='*'.__eq__) if not isstar]

这会将您的输入分组为*和非*的运行，丢弃*组，而tuple将非*组

Answer 2

使用itertools.groupby根据条目是否为*对条目进行分组，然后使用*（不相等）方法或使用__ne__保留不属于lambda的部分。等效的>>> import itertools >>> mylist = ['*', 'Drama', 'Film Noir', 'Mystery', 'Romance', '*', 'Dance', 'Drama', 'Musical', '*', 'Crime', 'Drama', '*', 'Action', 'Drama', 'Period', 'Western', '*', 'Adaptation', 'Based-on', 'Comedy', 'Romance', '*', 'Mystery', 'Thriller', '*', 'Comedy'] >>> [tuple(g) for k, g in itertools.groupby(mylist, key="*".__ne__) if k] [('Drama', 'Film Noir', 'Mystery', 'Romance'), ('Dance', 'Drama', 'Musical'), ('Crime', 'Drama'), ('Action', 'Drama', 'Period', 'Western'), ('Adaptation', 'Based-on', 'Comedy', 'Romance'), ('Mystery', 'Thriller'), ('Comedy',)]表达式：

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Python组列表元素按值分成元组

2 个答案: