Question

所以我想这样做（但使用pyparsing）

Package:numpy11 Package:scipy
will be split into
[["Package:", "numpy11"], ["Package:", "scipy"]]

到目前为止，我的代码是

package_header = Literal("Package:")
single_package =  Word(printables + " ") + ~Literal("Package:")
full_parser  = OneOrMore( pp.Group( package_header + single_package ) )

当前输出是这个

([(['Package:', 'numpy11 Package:scipy'], {})], {})

我希望有这样的东西

([(['Package:', 'numpy11'], {})], [(['Package:', 'scipy'], {})], {})

基本上其余的文本与pp.printables匹配

我知道我可以使用Word，但是我想这样做

all printables but not the Literal

我该如何完成？谢谢。

Answer 1

您不需要负前瞻，即。这个：

from pyparsing import *

package_header = Literal("Package:")
single_package =  Word(printables)
full_parser  = OneOrMore( Group( package_header + single_package ) )

print full_parser.parseString("Package:numpy11 Package:scipy")

打印：

[['Package:', 'numpy11'], ['Package:', 'scipy']]

更新：要解析由|分隔的软件包，您可以使用delimitedList()函数（现在软件包名称中也可以有空格）：

from pyparsing import *

package_header = Literal("Package:")
package_name = Regex(r'[^|]+')  # | is a printable, so create a regex that excludes it.
package = Group(package_header + package_name) 
full_parser = delimitedList(package, delim="|" )

print full_parser.parseString("Package:numpy11 foo|Package:scipy")

打印：

[['Package:', 'numpy11 foo'], ['Package:', 'scipy']]

根据pyparsing进行拆分

1 个答案: