Question

我有一个受重力影响的10个绘制矩形（在我的脚本中称为立方体）的列表。我为他们制作了一个简单的碰撞系统，让他们在落地时停下来。我该怎么做，当2个立方体碰撞时，它们像地面一样停止下落？

import pygame
import time
import random
pygame.init()
clock = pygame.time.Clock()
wnx = 800
wny = 600
black = (0,0,0)
grey = (75,75,75)
white = (255,255,255)
orange = (255,100,30)
wn = pygame.display.set_mode((wnx, wny))
wn.fill(white)
def cube(cx,cy,cw,ch):
    pygame.draw.rect(wn, orange, [cx, cy, cw, ch])
def floor(fx,fy,fw,fh):
    pygame.draw.rect(wn, grey, [fx, fy, fw, fh])
def main():
    floory = 550    
    number = 30
    cubex = [0] * number
    cubey = [0] * number
    cubew = 10                          
    cubeh = 10
    for i in range(len(cubex)):
        cubex[i] = (random.randrange(0, 80)*10)
        cubey[i] = (random.randrange(2, 5)*10)
    gravity = -10
    exit = False

    while not exit:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                exit = True
        for i in range(len(cubex)): #i want to check here if it collides with an other cube
            if not (cubey[i] + 10) >= floory:
                cubey[i] -= gravity

        wn.fill(white)
        floor(0,floory,800,50)

        for i in range(len(cubex)):
            cube(cubex[i], cubey[i], cubew, cubeh)

        pygame.display.update()
        clock.tick(5)
main()
pygame.quit()
quit()

Answer 1

使用pygame.Rect.colliderect检查矩形是否相交。

创建一个矩形（pygame.Rect），该矩形定义多维数据集的下一个位置（区域）：

cubeR = pygame.Rect(cubex[i], cubey[i] + 10, cubew, cubeh)

找到所有相交的矩形

cl = [j for j in range(len(cubey)) if j != i and cubeR.colliderect(pygame.Rect(cubex[j], cubey[j], cubew, cubeh))]

如果发生any()碰撞，请勿移动（让其进一步“掉落”）立方体：

if not any(cl):
    # [...]

支票可能看起来像这样：

for i in range(len(cubex)):
    cubeR = pygame.Rect(cubex[i], cubey[i] + 10, cubew, cubeh)
    cisect = [j for j in range(len(cubey)) if j != i and cubeR.colliderect(pygame.Rect(cubex[j], cubey[j], cubew, cubeh))]
    if not any(cisect) and not (cubey[i] + 10) >= floory:
        cubey[i] -= gravity

注意，由于所有多维数据集都对齐到10 * 10栅格，因此足以检查多维数据集的原点是否相等：

for i in range(len(cubex)):
    cisect = [j for j in range(len(cubey)) if j != i and cubex[i] == cubex[j] and cubey[i]+10 == cubey[j]]
    if not any(cisect) and not (cubey[i] + 10) >= floory:
        cubey[i] -= gravity

pygame：在同一列表中将矩形与其他矩形碰撞

1 个答案: