Question

我已经在makefile中定义了以下函数。

# check debug xdc
define check_debug_xdc
    if [ -f ${DEBUG_XDC} ]; then \
        ...
    fi
endef

如果直接调用，

make运行正常。

# Optimize
${OUTPUTS1}: ${INPUTS1}
    @echo ""
    @echo "Optimization"
    @date '+%Y_%m%d_%H%M'
    @$(call check_debug_xdc)

但是如果我注释掉DEBUG_XDC并将$(call check_debug_xdc)放在if-fi内以检查DEBUG_XDC是否已定义，请停止响应，没有输出任何内容，甚至日期也没有。

# DEBUG_XDC     = ./fpga_ila/fpga_ila.srcs/constrs_1/new/${TOP}.xdc  
...
# Optimize
${OUTPUTS1}: ${INPUTS1}
    @echo ""
    @echo "Optimization"
    @date '+%Y_%m%d_%H%M'
    @if [ ! -z "${DEBUG_XDC}" ]; then $(call check_debug_xdc); fi

尝试使用-dn，它将在消息下方显示，然后停止响应。

GNU Make 3.81
Copyright (C) 2006  Free Software Foundation, Inc.
This is free software; see the source for copying conditions.
There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A
PARTICULAR PURPOSE.

This program built for i686-pc-linux-gnu
Reading makefiles...
Reading makefile `makefile'...
Updating makefiles....
 Considering target file `makefile'.
    ...
         Finished prerequisites of target file `fpga/fpga_opt.dcp'.
        Must remake target `fpga/fpga_opt.dcp'.

如何解决？

为什么make被锁定？

0 个答案: