我在下面具有以下功能:
Range.Select
,然后退出选定范围的函数。代码如下:
Function find_Header(header As String, fType As String)
Dim aCell As Range, rng As Range
Dim col As Long, lRow As Long
Dim colName As String
With ActiveSheet
Set aCell = .Range("B2:J2").Find(What:=header, LookIn:=xlValues, LookAt:=xlWhole, MatchCase:=False, SearchFormat:=False)
'If Found
If Not aCell Is Nothing Then
col = aCell.Column
colName = Split(.Cells(, col).Address, "$")(1)
lRow = Range(colName & .Rows.count).End(xlUp).Row + 1
Set myCol = Range(colName & "2")
Select Case fType
Case "Copy"
'This is your range
Set rng = Range(myCol.Address & ":" & colName & lRow).Offset(1, 0)
rng.Select
End Select
'If not found
Else
MsgBox "Column Not Found"
End If
End With
End Function
在尝试清理代码时,我遇到了一个专门对区域进行硬编码的部分,而我试图使用我的函数,但是,现在我无法使用正确使用此功能,因为我无法将范围“传递”给子对象,而且似乎无法使选择成为子对象所需的范围对象。
以下是子内容:
Sub Copy_Failed()
Dim xRg As Range, xCell As Range
Dim i As Long, J As Long, count As Long
Dim fType As String, colName As String
Dim y As Workbook
Dim ws1 As Worksheet, ws2 As Worksheet
myarray = Array("Defect", "System", "Script")
myEnv = Array("SIT", "UAT")
myDefects = Array("New", "Existing")
i = Worksheets("Run Results").UsedRange.Rows.count
J = Worksheets("Failed").UsedRange.Rows.count
Set y = Workbooks("Template.xlsm")
Set ws1 = y.Sheets("Failed")
Set ws2 = y.Sheets("Run Results")
count = 3
If J = 1 Then
If Application.WorksheetFunction.CountA(ws1.UsedRange) = 0 Then J = 0
End If
ws2.Activate
fType = "Copy"
colName = "Status"
Call find_Header(colName, fType)
End Sub
在使用该功能之前,代码如下:
lngLastRow = Cells(Rows.count, "B").End(xlUp).Row
Set xRg = ws2.Range("E3:E" & lngLastRow & i)
现在这2行是在函数中执行的,因此在子例程中不需要它。我尝试了以下方法:
Set rngMyRange = Selection
Set rngMyRange = ActiveSheet.Range(Selection.Address)
Set xRg = ws2.Range(rngMyRange & i)
但是我得到了错误:
类型不匹配
所以我在想:
尽管第二个选项需要对我的代码进行一些额外的更改,但我认为这是一个更好的选择。
答案 0 :(得分:2)
好的,这是一个例子,以便您明白我的意思。如果在B2:J2中的某个位置放置“一个”,它将选择范围。我仅在此处使用“选择”,以便您可以看到其标识的范围。 (免责声明:我不太了解您在做什么,并且不确定您是否需要所有这些代码来实现所需的功能。)
该函数现在返回一个范围变量,并被分配给r
。运行过程x
。
Sub x()
Dim r As Range
Set r = Range("a1", find_Header("one", "Copy"))
r.Select
End Sub
Function find_Header(header As String, fType As String) As Range
Dim aCell As Range, rng As Range
Dim col As Long, lRow As Long
Dim colName As String
With ActiveSheet
Set aCell = .Range("B2:J2").Find(What:=header, LookIn:=xlValues, LookAt:=xlWhole, MatchCase:=False, SearchFormat:=False)
'If Found
If Not aCell Is Nothing Then
col = aCell.Column
colName = Split(.Cells(, col).Address, "$")(1)
lRow = Range(colName & .Rows.Count).End(xlUp).Row + 1
Set myCol = Range(colName & "2")
Select Case fType
Case "Copy"
'This is your range
Set find_Header = Range(myCol.Address & ":" & colName & lRow).Offset(1, 0)
End Select
'If not found
Else
Set find_Header = Nothing
End If
End With
End Function