我上课
public enum CustomerType {
GOLD, SILVER, IRON, RUSTY
}
和另一个班级:
@Entity
公共类Customer实现了可序列化的{
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
private String firstName;
private String lastName;
private CustomerType type;
public Customer(){};
public Customer(String firstName, String lastName){
this.firstName = firstName;
this.lastName = lastName;
}
public Customer(String firstName, String lastName, CustomerType type){
this.firstName = firstName;
this.lastName = lastName;
this.type = type;
}
public String getFirstName(){ return firstName;}
public String getLastName(){ return lastName;}
public Integer getId() { return id; }
public CustomerType getType(){ return type;}
public void setId(Integer id) { this.id = id;}
public void setFirstName(String firstName){this.firstName = firstName;}
public void setLastName(String lastName ){this.lastName = lastName;}
public void setType(CustomerType type){this.type = type;}
@Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
@Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Customer)) {
return false;
}
Customer other = (Customer) object;
if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
return false;
}
return true;
}
@Override
public String toString() {
return "entity.Customer[ id=" + id + " ]";
}
}
我有一个构造函数,其参数为firstName,lastName,CustomerType类型
我要在另一个班级中创建这样的客户
Customer c1 = new Customer("ida", "heartless", GOLD);
但是它不会像这样放枚举参数。如何正确使用枚举?我想念的是什么?
答案 0 :(得分:2)
看起来您只需要在Customer
类中导入即可。
然后它应该看起来像这样:
Customer c1 = new Customer("ida", "heartless", CustomerType.GOLD);
答案 1 :(得分:1)
您需要添加CustomerType.GOLD
而不是GOLD
。