Question

我陷入了一个难题，无法按日期获取多个员工的多个产品数据，这不知道如何解决。

主表/表1-在此数量中，常数始终为1

SNo | EmpName | LblCode | DateOfSour | ProdType | Amount
1   |  Emp1   |   001   | 2019-01-01 |  Prod1   | 1
2   |  Emp1   |   001   | 2019-01-01 |  Prod2   | 1
3   |  Emp2   |   002   | 2019-01-02 |  Prod1   | 1
4   |  Emp1   |   001   | 2019-01-01 |  Prod1   | 1
5   |  Emp3   |   003   | 2019-01-01 |  Prod2   | 1
6   |  Emp2   |   002   | 2019-01-03 |  Prod2   | 1

欲望的结果

EmpName |DateOfSour| LblCode |  Prod1 | Prod2 | Prod3 |DateOfSour|  Prod1 | Prod2 | Prod3 |DateOfSour|  Prod1 | Prod2 | Prod3 |
Emp1    |2019-01-01|   001   |    2   |   1   |   0   |2019-01-02|    0   |   0   |   0   |2019-01-03|    0   |   0   |   0   |
Emp2    |2019-01-01|   002   |    0   |   0   |   0   |2019-01-02|    1   |   0   |   0   |2019-01-03|    0   |   1   |   0   |
Emp3    |2019-01-01|   003   |    0   |   1   |   0   |2019-01-02|    0   |   0   |   0   |2019-01-03|    0   |   0   |   0   |
Total   |2019-01-01|         |    2   |   2   |   0   |2019-01-02|    1   |   0   |   0   |2019-01-03|    0   |   1   |   0   |

我尝试了以下代码，但失败了，但这是这种格式所能达到的最大我使用的代码：

SELECT  
      DateOfSour,
      ISNULL(EMPName,'Total')as EmpName,
      IsNULL(LblCode,'') as LblCode ,
      SUM(CASE WHEN ProdType='Prod1' THEN Amount ELSE 0 END) as Prod1,
      SUM(CASE WHEN ProdType='Prod2' THEN Amount ELSE 0 END) as Prod2,
      SUM(CASE WHEN ProdType='Prod3' THEN Amount ELSE 0 END) as Prod3,
FROM Table1
  WHERE DateOfSour between('2019-01-01') and ('2019-01-03') 
  GROUP BY DateOfSour, GROUPING SETS((EMPName,LblCode), ())

我使用SQL Server 2008。

编辑1：这只是两天的一个例子，我想要给定随机日期

Answer 1

您需要更多列。像这样：

SELECT COALESCE(EMPName, 'Total') as EMPName,       
       COALESCE(LblCode, '') as LblCode ,
       '2019-01-01' as DateOfSour1,
       SUM(CASE WHEN DateOfSour = '2019-01-01' AND ProdType = 'Prod1' THEN Amount ELSE 0 END) as Prod1_1,
       SUM(CASE WHEN DateOfSour = '2019-01-01' AND ProdType = 'Prod2' THEN Amount ELSE 0 END) as Prod2_1,
       SUM(CASE WHEN DateOfSour = '2019-01-01' AND ProdType = 'Prod3' THEN Amount ELSE 0 END) as Prod3_1,
       '2019-01-02' as DateOfSour2,
       SUM(CASE WHEN DateOfSour = '2019-01-02' AND ProdType = 'Prod1' THEN Amount ELSE 0 END) as Prod1_2,
       SUM(CASE WHEN DateOfSour = '2019-01-02' AND ProdType = 'Prod2' THEN Amount ELSE 0 END) as Prod2_2,
       SUM(CASE WHEN DateOfSour = '2019-01-02' AND ProdType = 'Prod3' THEN Amount ELSE 0 END) as Prod3_2
FROM Table1
WHERE DateOfSour IN (''2019-01-01', '2019-01-02') 
GROUP BY GROUPING SETS((EMPName, LblCode), ())

sql中多个员工的日期明智的多个产品数据

1 个答案: