Question

{
  "status": "1",
  "message": "",
  "result": {
    "info": {
      "tax": "0",
      "discount": "0",
      "minimum_spend": "300",
      "delivery_charges": "0",
      "last_updated": "1 week 15 hours ago"
    },
    "items": [
      {
        "name": "Eat At Home",
        "menu_item_id": "12345",
        "menu_cat_id": "4321",
        "menu_cat_sku": "",
        "nutritions": "",
        "price": "1000",
        "currency": "USD",
        "desc": "Desription",
        "category": "Promotion",
        "image": "https://static.google.com/media/images/thumbs/343e8f41b18325a6058adc3773ed4d53.png",
        "large_image": "https://static.google.com/media/images/343e8f41b18325a6058adc3773ed4d53.png",
        "options": [],
        "discount": "",
        "weight": "",
        "sku": "",
        "status": "0",
        "brand": []
      },
      {
        "name": "Lunch Bundle",
        "menu_item_id": "4321",
        "menu_cat_id": "4321",
        "menu_cat_sku": "",
        "nutritions": "",
        "price": "1500",
        "currency": "USD",
        "desc": "Description",
        "category": "Promotion",
        "image": "https://static.google.com/media/images/thumbs/62cdde279bbc3e45b8456f040d649b32.png",
        "large_image": "https://static.google.com/media/images/62cdde279bbc3e45b8456f040d649b32.png",
        "options": [],
        "discount": "",
        "weight": "",
        "sku": "",
        "status": "0",
        "brand": []
      },

我的代码

MenuResponse menuResponse = JsonParser.getInstance().parseMenuResponse(response);


public MenuResponse parseMenuResponse(String serverResponse) throws Exception {

    MenuResponse response = null;

    if (serverResponse != null) {
        try {
            response = gson.fromJson(serverResponse, MenuResponse.class);
        } catch (JsonSyntaxException jse) {
            throw new Exception(ERROR_MESSAGE);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    return response;
}

Answer 1

尝试一下。

JSONObject json = new JSONObject(response);

 String status= json.getString("status");
 JSONArray itemsArray= json.getJSONArray("items");

for (int i = 0; i < itemsArray.length(); i++) {
 JSONObject c = itemsArray.getJSONObject(i);
 String name= c.getString("name");
 //remaining data you will 
}

或者更好，您可以使用翻新。

如何使用Volley和POJO类在Android中解析嵌套的JSON对象

1 个答案:

尝试一下。