我如何将这个json.dumps（）传递给函数使用？

Question

如何将结果传递给display_function？

def some_function ():
    url = "someurl"
    data = requests.get(url).json()
    result = json.dumps(data)
    display_function(result)

def display_function (result): ## get's json.dumps(data) to use and display to html in this function
    output = "some html goes here:" + result 
    return output

Answer 1

您仅定义函数，但从未真正调用它们。您可以尝试像这样重写脚本：

joe

您还可以通过以下调整来测试它是否通过：

def some_function ():
    url = "someurl"
    data = requests.get(url).json()
    result = json.dumps(data)
    main_result = display_function(result)
    return main_result

def display_function (result): ## get's json.dumps(data) to use and display to html in this function
    output = "some html goes here:" + result 
    return output

if __name__ == "__main__":
    my_results_wanted = somefunction()