Question

现在我正在处理我的第一个python项目。假设从YouTube搜索中随机提取一个视频，然后将其添加到Watch2Gether。现在，我的代码如下：

# Take a random video from my youtube recommended and add it to watch2gether
import requests
from bs4 import BeautifulSoup as BS
import time
import random
from fake_useragent import UserAgent
# Importing libraries

def GetVideos(): # Function to generate videos from youtube

    num = random.randint(1, 20)
    recommended = requests.get('https://www.youtube.com/results?search_query=svenska+youtube+klassiker&sp=EgIQAQ%253D%253D')
    recommended_soup = BS(recommended.content, features='lxml')
    all_links = recommended_soup.find_all('a', href=True)
    my_links = [] #Just a empty list to story all /watch links

    for link in all_links:
        if '/watch' in link['href']:
            print(link['href'])
            my_links.append(link['href'])
#check for all the /watch and appends them to my emty list

    print('www.youtube.com' + my_links[num])

ua = UserAgent()
print(ua.random)
URL = "https://www.watch2gether.com/rooms/zgabjnblvqy52vam0c"
r = requests.get(URL, data={'class': 'w2g-messages-input'})
# And done.
print(r.text) # displays the result body.

我的目标是使我的程序加入我的“房间”，然后添加随机视频。我已经找到了如何获取视频的所有链接，但无法将它们发布到“房间”中。感谢所有帮助！ :)如果您需要更多信息，请发表评论。

Answer 1

如评论中所述，首先要做的是将requests.get更改为requests.post。

我也建议您将data={'class': 'w2g-messages-input'}更改为json={'class': 'w2g-messages-input'}。

因此您发送请求的代码行将如下所示：

r = requests.post(URL, json={'class': 'w2g-messages-input'})

希望这会有所帮助。

如何在Python中发布带有请求的链接

1 个答案: