将RestSharp Reqest AddParameter转换为POST请求的JavaScript数据

时间:2019-02-19 18:05:42

标签: javascript c# post restsharp rest-client

有人会知道RestSharp的含义吗?

request.AddParameter("text/plain", body, ParameterType.RequestBody);

使用Javascript?那是我唯一想念的部分。

这是C#中的有效代码:

        public static void UploadFile(string bearer)
    {
        var client = new RestClient("...");
        var request = new RestRequest(Method.POST);
        request.AddHeader("Authorization", "Bearer " + bearer);
        request.AddHeader("cache-control", "no-cache");

        var imageLenngth = new FileInfo(@"...").Length;

        request.AddHeader("Content-Type", "image/jpeg");
        request.AddHeader("Content-Length", imageLenngth.ToString());

        byte[] body = File.ReadAllBytes(@"...");

        request.AddParameter("text/plain", body, ParameterType.RequestBody);

        IRestResponse response = client.Execute(request);
    }

并且在Ajax JavaScript中代码不能完全正常工作(它会上传到云服务器,但是上传的图像不正确。插入损坏的图像的字节数太多了)

    function uploadingImage(binaryImage) {
        
        var settings = {
            "async": true,
            "crossDomain": true,
            "url": "...",
            "method": "POST",
            "headers": {
                "Content-Type": "image/jpeg",
                "Authorization": "Bearer ...",
                "cache-control": "no-cache",
            },
            "data": binaryImage
        }

        $.ajax(settings).done(function (response) {
            console.log(response);
        });
    }

1 个答案:

答案 0 :(得分:0)

我发现了问题。提琴手帮助调查了发送的内容。默认情况下,传入的数据将被序列化。为防止这种情况,我们需要明确告知不要序列化它。 “ processData”:假的把戏。这是工作代码:

    function uploadingImage(binaryImage) {
        
        var settings = {
            "async": true,
            "crossDomain": true,
            "url": "...",
            "method": "POST",
            "headers": {
                "Content-Type": "image/jpeg",
                "Authorization": "Bearer ...",
                "cache-control": "no-cache",
            },
            "processData":false,
            "data": binaryImage
        }

        $.ajax(settings).done(function (response) {
            console.log(response);
        });
    }