Question

我正在整理自己的分类资料，并且遇到了障碍。我可以按特定字段排序，但方向仍然是硬编码。

@PreAuthorize("hasAuthority('service_manager')")
    @RequestMapping(path = "/clients", method = RequestMethod.GET)
    public Page<ClientResponse> getClients(
            @RequestParam(defaultValue = "0") Integer page,
            @RequestParam(defaultValue = "10") Integer size,
            @RequestParam(required = false) String companyName,
            @RequestParam(required = false) BigInteger firmRegNo,
            @RequestParam(required = false) String address,
            @RequestParam(required = false) BigInteger contractNo,
            @RequestParam(required = false) BigInteger monthlyPay,
            @RequestParam(required = false) User.UserStatus status,
            @RequestParam(defaultValue = "createTime") String sort,
            @RequestParam(defaultValue = "desc") String sortDir
            ) {

        ClientListRequest request = new ClientListRequest(companyName, firmRegNo, address, contractNo, monthlyPay, status);
        return clientService.getAllClients(request, of(page, size, Sort.Direction.DESC, sort))
                .map(ClientResponse::new);
    }

如何根据Sort.Direction.DESC的参数值交替使用Sort.Direction.ASC和sortDir？

我尝试过：

if (sortDir == "asc") {
            return clientService.getAllClients(request, of(page, size, Sort.Direction.ASC, sort))
                    .map(ClientResponse::new);
        } else {
            return clientService.getAllClients(request, of(page, size, Sort.Direction.DESC, sort))
                    .map(ClientResponse::new);
        }

不起作用，看起来也不正确...

Answer 1

尝试这样的事情：

    Pageable pageable = new PageRequest(page, size, Sort.Direction.fromString(sortDir), sort);
    return repository.findAll(pageable);

Answer 2

我用了这个：

Sort.Direction direction;

        if (sortDir.equals("asc")) {
            direction = Sort.Direction.ASC;
        } else {
            direction = Sort.Direction.DESC;
        }

        return clientService.getAllClients(request, of(page, size, direction, sort))
                    .map(ClientResponse::new);

服务器端排序，ASC / DESC

2 个答案: