Question

我一直在搜索，但没有任何答案能满足我的需求。对于此分配，我们得到了一个列表，但是我需要从该列表中打印出特定元素，以便看起来像这样，但是我需要使用用户输入来搜索该列表：/

Employee Name: Jeffery Medina
Salary: 101442.00
Age: 23

这是我的清单

lst=[('Jeffery Medina','Officer','1254','101442.00','23'),('Katrina Peters','Officer','3423','94122.00','45'),('Kim Alan','Captain','6434','101592.00','29'),('Vincente Mendez','Officer','3235','110064.00','32'),('Chris Boalen','Captain','8769','50436.00','56'),('James Vito','Clerk','4451','23500.00','61'),('Terry George','Fireman','3342','93354.00','32'),('Zaid Dane','Officer','2345','84054.00','19'),('Ernesto Rodriguez','Officer','9091','87006.00','35'),('Josefine White','Fireman','3401','102228.00','26'),('Mario Infante','Officer','3234','84054.00','22'),('Juan Almonte','Fireman','4103','91272.00','50'),('Kevin Smith','Fireman','3450','111492.00','62'),('Abdum Smith','Captain','2234','95484.00','20'),('Juan Gomez','Clerk','9023','23890.00','49')]

对于用户输入，我只是使用了这个： name=input("Who are you looking for? :")

谢谢

Answer 1

具有列表理解功能：

data = [('Jeffery Medina','Officer','1254','101442.00','23'),('Katrina Peters','Officer','3423','94122.00','45'),('Kim Alan','Captain','6434','101592.00','29'),('Vincente Mendez','Officer','3235','110064.00','32'),('Chris Boalen','Captain','8769','50436.00','56'),('James Vito','Clerk','4451','23500.00','61'),('Terry George','Fireman','3342','93354.00','32'),('Zaid Dane','Officer','2345','84054.00','19'),('Ernesto Rodriguez','Officer','9091','87006.00','35'),('Josefine White','Fireman','3401','102228.00','26'),('Mario Infante','Officer','3234','84054.00','22'),('Juan Almonte','Fireman','4103','91272.00','50'),('Kevin Smith','Fireman','3450','111492.00','62'),('Abdum Smith','Captain','2234','95484.00','20'),('Juan Gomez','Clerk','9023','23890.00','49')]
name = input('Who are you looking for: ')
print([x for x in data if name in x[0]])

输出：

Who are you looking for: Jeffery
[('Jeffery Medina', 'Officer', '1254', '101442.00', '23')]

Answer 2

请勿将关键字list用作变量名。
您可以遍历list的长度，并检查name是否等于其第一个索引的第一个元素。

因此：

lst=[('Jeffery Medina','Officer','1254','101442.00','23'),('Katrina Peters','Officer','3423','94122.00','45'),('Kim Alan','Captain','6434','101592.00','29'),('Vincente Mendez','Officer','3235','110064.00','32'),('Chris Boalen','Captain','8769','50436.00','56'),('James Vito','Clerk','4451','23500.00','61'),('Terry George','Fireman','3342','93354.00','32'),('Zaid Dane','Officer','2345','84054.00','19'),('Ernesto Rodriguez','Officer','9091','87006.00','35'),('Josefine White','Fireman','3401','102228.00','26'),('Mario Infante','Officer','3234','84054.00','22'),('Juan Almonte','Fireman','4103','91272.00','50'),('Kevin Smith','Fireman','3450','111492.00','62'),('Abdum Smith','Captain','2234','95484.00','20'),('Juan Gomez','Clerk','9023','23890.00','49')]

name = input("Who are you looking for? :")

for i in range(len(lst)):
    try:
        if name == lst[i][i]:
            print("Employe Name: {} \nSalary: {} \nAge: {} ".format(lst[i][i], lst[i][i+3], lst[i][i+4]))
    except IndexError:
        pass

输出：

Who are you looking for? :Jeffery Medina
Employe Name: Jeffery Medina 
Salary: 101442.00 
Age: 23

编辑：

使用正则表达式的另一种解决方案将消除区分大小写的需求。

for i in range(len(lst)):
    try:
        if re.search(name, lst[i][i], re.IGNORECASE):
            print("Employe Name: {} \nSalary: {} \nAge: {} ".format(lst[i][i], lst[i][i+3], lst[i][i+4]))
    except IndexError:
        pass

输出：

Who are you looking for? :jeFFerY mEdinA
Employe Name: Jeffery Medina 
Salary: 101442.00 
Age: 23

Answer 3

list=[('Jeffery Medina','Officer','1254','101442.00','23'),('Katrina Peters','Officer','3423','94122.00','45'),('Kim Alan','Captain','6434','101592.00','29'),('Vincente Mendez','Officer','3235','110064.00','32'),('Chris Boalen','Captain','8769','50436.00','56'),('James Vito','Clerk','4451','23500.00','61'),('Terry George','Fireman','3342','93354.00','32'),('Zaid Dane','Officer','2345','84054.00','19'),('Ernesto Rodriguez','Officer','9091','87006.00','35'),('Josefine White','Fireman','3401','102228.00','26'),('Mario Infante','Officer','3234','84054.00','22'),('Juan Almonte','Fireman','4103','91272.00','50'),('Kevin Smith','Fireman','3450','111492.00','62'),('Abdum Smith','Captain','2234','95484.00','20'),('Juan Gomez','Clerk','9023','23890.00','49')]

name = input("Who are you looking for? :")
for i in range(len(list)):
    if list[i][0] == name:
        print("Employe Name: {} \nSalary: {} \nAge: {} ".format(name,str(list[i][3]),str(list[i][4])))

结果：

您在寻找谁？：杰弗里·麦地那（Jeffery Medina）

员工姓名：Jeffery Medina

工资：101442.00

年龄：23

Answer 4

您有一个元组列表。您的用户输入将是一个名称，因此一种基本方法是检查每个元组是否有此特定名称：

CascadeType.ALL

Answer 5

您必须检查列表中的每个人，如果用户输入的名称与每个人的第一项（名称）相匹配，请打印出他们的所有信息。

此外，我建议您将列表重命名为“列表”以外的名称，因为以后可能会造成混淆！

while True:
    name = input("Who are you looking for?: ")

    for person in people:
        if person[0] == name:
            print("Name: {},\nRank: {},\nNumber: {},\nSalary: {},\nAge: {}".format(person[0],person[1],person[2],person[3],person[4]))
            break
        else:
            print("This person does not exist. Try Another")

希望这会有所帮助， -内特

如何使用Python中的用户输入来打印列表的特定部分

5 个答案: