Question

我要导出文件夹子集的文件夹权限。 Department中的每个文件夹都有两个子文件夹，Public和Internal。

例如，我需要文件夹D:\Data\Department\Science\Public或D:\Data\Department\Sales\Public的权限。

$FolderPath = dir -Directory -Path "D:\Data\Department" -Force
$Report = @()
Foreach ($Folder in $FolderPath) 
{
$Folder2 = Join-Path -Path $Folder -ChildPath "Public"

$Acl = Get-Acl $Folder2.FullName

foreach ($Access in $acl.Access)
{
$Properties = [ordered]@{'FolderName'=$Folder2.FullName;'AD
Group or User'=$Access.IdentityReference;'Permissions'=$Access.FileSystemRights;'Inherited'=$Access.IsInherited}
$Report += New-Object -TypeName PSObject -Property $Properties
}
}
$Report | Export-Csv -path "C:\Users\adminrw\FolderPermissions.csv"

错误：

Get-Acl : Cannot validate argument on parameter 'Path'. The argument is null or empty. Provide an argument that is not null or empty, and then try the command again.
At line:7 char:16
+ $Acl = Get-Acl $Folder2.FullName
+                ~~~~~~~~~~~~~~~~~
    + CategoryInfo          : InvalidData: (:) [Get-Acl], ParameterBindingValidationException

Answer 1

看起来脚本中的Join-Path正在使用文件夹的名称并将子路径添加到该路径。这导致$Folder2最终像SomeFolder\Public

尝试使用

$Folder2 = Join-Path -Path $Folder.FullName -ChildPath "Public"

这将使$Folder2：D:\Data\Department\SomeFolder\Public

Answer 2

我已更正脚本。请使用以下代码：

$FolderPath = dir -Directory -Path "D:\Data\Department" -Force | Select *
$Report = @()
Foreach ($Folder in $FolderPath) 
{
$Folder2 = Join-Path -Path $Folder.FullName -ChildPath "Public"

$Acl = Get-Acl $Folder2

foreach ($Access in $acl.Access)
{
$Properties = [ordered]@{'FolderName'=$Folder2.FullName;'AD
Group or User'=$Access.IdentityReference;'Permissions'=$Access.FileSystemRights;'Inherited'=$Access.IsInherited}
$Report += New-Object -TypeName PSObject -Property $Properties
}
}
$Report | Export-Csv -path "C:\Users\adminrw\FolderPermissions.csv"

导出文件夹权限

2 个答案: