Question

任何人都可以解释为什么即使我已经使用sum和group by子句时仍然得到两个相同的列名吗？

这是我在postgres中的查询：

SELECT tbl_boxes.box_name                          AS "BOX NAME",
       tbl_stores.store_name                       AS "STORE NAME",
       tbl_sku.sap_name                            AS "SKU NAME",
       SUM(tbl_bad_orders_product.quantity_pcs)    AS "QUANTITY PER PIECE",
       SUM(tbl_bad_orders_product.price_per_piece) AS "PRICE PER PIECE",
       SUM(tbl_bad_orders_product.quantity_cs)     AS "QUANTITY PER CASE",
       SUM(tbl_bad_orders_product.price_per_case)  AS "PRICE PER CASE",
       tbl_bad_orders_product.reason               AS "REASON",
       SUM(tbl_bad_orders_product.total_amount)    AS "TOTAL AMOUNT",
       tbl_bad_orders_product.date_created         AS "DATE CREATED",
       tbl_bad_orders_product.date_updated         AS "DATE UPDATED",
       tbl_bad_orders_product.date_sync            AS "DATE SYNCED"
FROM tbl_bad_orders_product
       INNER JOIN tbl_users ON tbl_bad_orders_product.tbluserid = tbl_users.tbluserid
       INNER JOIN tbl_boxes ON tbl_bad_orders_product.tblboxid = tbl_boxes.tblboxesid
       INNER JOIN tbl_stores ON tbl_bad_orders_product.tblstoreid = tbl_stores.tblstoreid
       INNER JOIN tbl_sku ON tbl_bad_orders_product.tblskuid = tbl_sku.tblskuid
WHERE tbl_bad_orders_product.date_sync::date >= '2019-02-19'
  AND tbl_bad_orders_product.date_sync::date <= '2019-02-19'
GROUP BY tbl_boxes.box_name, tbl_stores.store_name, tbl_sku.sap_name, tbl_bad_orders_product.quantity_pcs,
         tbl_bad_orders_product.price_per_piece, tbl_bad_orders_product.quantity_cs,
         tbl_bad_orders_product.price_per_case, tbl_bad_orders_product.reason, tbl_bad_orders_product.total_amount,
         tbl_bad_orders_product.date_created, tbl_bad_orders_product.date_updated, tbl_bad_orders_product.date_sync
ORDER BY tbl_boxes.box_name ASC

但是我得到了这个输出：

请帮助我解决问题。

Answer 1

基本上，您要在SELECT中包含来自 tbl_bad_orders （ quantity_pcs ， price_per_piece ， quantity_cs ， price_per_case ，总金额）在GROUP BY子句中，由于您运行了聚合函数SUM，几乎不需要聚合，按其价值分组。

只需从SUM子句中删除GROUP BY聚合中使用的这些数字字段。另外，考虑表别名的可读性和可维护性。还考虑对结果集左侧的分组列和右侧的聚合列在SELECT中的字段进行重新排序。最后，您的WHERE条件可能是多余的。

SELECT b.box_name                  AS "BOX NAME",
       s.store_name                AS "STORE NAME",
       sku.sap_name                AS "SKU NAME",
       bad.reason                  AS "REASON",
       bad.date_created            AS "DATE CREATED",
       bad.date_updated            AS "DATE UPDATED",
       bad.date_sync               AS "DATE SYNCED",
       SUM(bad.quantity_pcs)       AS "QUANTITY PER PIECE",
       SUM(bad.price_per_piece)    AS "PRICE PER PIECE",
       SUM(bad.quantity_cs)        AS "QUANTITY PER CASE",
       SUM(bad.price_per_case)     AS "PRICE PER CASE",
       SUM(bad.total_amount)       AS "TOTAL AMOUNT"
FROM tbl_bad_orders_product AS bad
     INNER JOIN tbl_users AS u ON bad.tbluserid = u.tbluserid
     INNER JOIN tbl_boxes AS b ON bad.tblboxid = b.tblboxesid
     INNER JOIN tbl_stores AS s ON bad.tblstoreid = s.tblstoreid
     INNER JOIN tbl_sku AS sku ON bad.tblskuid = sku.tblskuid
WHERE bad.date_sync::date >= '2019-02-19'
  AND bad.date_sync::date <= '2019-02-19'
GROUP BY b.box_name, 
         s.store_name, 
         sku.sap_name, 
         bad.reason,
         bad.date_created, 
         bad.date_updated, 
         bad.date_sync
ORDER BY b.box_name ASC

使用GROUP BY函数在INNER JOINING中执行求和不起作用Postgresql

1 个答案: