Question

我正在使用For循环遍历一个表。当某行满足某个条件时，我将从for循环中断。但是根据我的代码，FOR似乎异步运行，导致并行迭代，而我不希望我的程序这样做。有人可以解决我认为是由于承诺解决而导致的这个问题。

element.all(by.css('tbody tr')).then(function(rows){
    for(var i = 1; i < (rows.length); i++) {
        var count=0;
        var pass=0;
        //TEST VALUES BELOW
        var appNameCreated="Test App 534";
        //TEST VALUES ABOVE
        console.log(i);
        element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(1)')).getText().then(function(appname){
            console.log(i,appname);
            if(appname==appNameCreated){
                console.log(appname,appNameCreated,i);
                element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(6)')).getText().then(function(result){
                    console.log(result,i);
//                  if (result==data.resultSubmit){
                    if (result=="Activated"){
                        pass += 1;
                        element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(1)')).element(by.css('a')).click().then(function(){
                            browser.sleep(4000);
                        });
                        element(by.id("btnTab3")).element(by.xpath('span')).click();
                        browser.wait(EC.visibilityOf(element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr[1]/td[1]'))),15000);                                   browser.wait(EC.visibilityOf(element(by.id("button-basic"))),15000);
                        browser.wait(EC.visibilityOf(element(by.id("button-basic"))),15000);
                        element(by.id("button-basic")).click();
                        element.all(by.css('ul[class="dropdown-menu"]')).each(function(item1){
                            item1.element(by.css('li:nth-child(7)')).element(by.css('a')).click();
                        })
                        element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+i+']')).element(by.css('td:nth-child(6)')).getText().then(function(resultFin){
                            console.log(resultFin);
                            browser.actions().mouseMove(element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(1)'))).perform();
                            expect(resultFin).toBe(data.resultFinal);
                        })
                    }
                })  
            }
        })
        if(pass==1){
            break;
        }
    }
})

Answer 1

更新您的代码： -使用async ... await更改承诺解决 -将var更改为let, const -循环计数应从0开始而不是1 -将==更改为=== -.each()无法与click()一起用于异步操作问题： -从哪里获取data.resultSubmit？

const rows = await element.all(by.css('tbody tr'));
const appNameCreated = "Test App 534";
let count = 0;
let pass = 0;
for (let i = 0; i < rows.length; i++) {
  console.log('Index is ', i);
  const appname = await element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(1)')).getText();
  console.log('App name for current loop is ', appname);
  if(appname === appNameCreated) {
    console.log('App name is the same as created app name for loop with index ', i);
    const result = await element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(6)')).getText();
    console.log('Result for current run is ' result);
    if (result === data.resultSubmit && result === "Activated") {                                 
      pass += 1;
      await element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(1)')).element(by.css('a')).click();
      await browser.sleep(4000);
    });
    await element(by.id("btnTab3")).element(by.xpath('span')).click();
    await browser.wait(EC.visibilityOf(element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr[1]/td[1]'))),15000);                                   
    await browser.wait(EC.visibilityOf(element(by.id("button-basic"))),15000);
    await browser.wait(EC.visibilityOf(element(by.id("button-basic"))),15000);
    await element(by.id("button-basic")).click();
    const menus = await element.all(by.css('ul[class="dropdown-menu"]'));
    const amount = await menus.count();
    for (let i = 0; i < amount; i++) {
     const item = await menus.get(i);
     await item.element(by.css('li:nth-child(7)')).element(by.css('a')).click();
    }
    const resultFin = await element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+i+']')).element(by.css('td:nth-child(6)')).getText();
   console.log('resultFin is ', resultFin);
   await browser.actions().mouseMove(element(by.xpath('/html/body/gft-root/section/div[2]/app-onboard-list/div[4]/div[3]/table/tbody/tr['+ i +']')).element(by.css('td:nth-child(1)'))).perform();
   expect(resultFin).toBe(data.resultFinal);
 })
}
 })  
 }
 })
if(pass ===1 ){
 break;
                }
            }
        })

我尽力消除了所有错误。您的代码很糟糕，因为您没有大笔的“那里到底是什么？”较小的功能。

Answer 2

您可以使用类似数组的对象的<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0"> <meta http-equiv="X-UA-Compatible" content="ie=edge"> <title>Float test</title> <link rel="stylesheet" href="./css/styles.css"> </head> <body> <div class="left-container"> <div class="left-container-heading">Lorem Ipsum</div> <br> <br> <p>Float left doesn't work anymore since it is more than one line and I would like to know why and how to fix this. </p> </div> </body> </html>来迭代行，并在满足条件的行中使用reduce()来中断循环。

由于您拒绝了诺言，因此应使用Promise.reject()来捕获诺言，然后单击匹配的行以进入下一页并进行操作，然后返回Promise.catch()内的表格页

catch()

量角器：For循环异步运行，导致测试运行无效的验证

2 个答案: