Question

我需要在JUnit中介绍XMLStreamException，但我不知道如何触发此异常。这是我班上的代码片段

    try {
        writer.add(factory.createStartElement("", "", BatchConstants.HEADER));
        writer.add(factory.createStartElement("", "", BatchConstants.MESSAGE_TYPE));
        writer.add(factory.createCharacters(BatchConstants.LPR_ENTITY));
        writer.add(factory.createEndElement("", "", BatchConstants.MESSAGE_TYPE));
        writer.add(factory.createStartElement("", "", BatchConstants.SEND_DATETIME));
        writer.add(factory.createCharacters(batchProcessControlEntity.getCreatedDt().toString()));
        writer.add(factory.createEndElement("", "", BatchConstants.SEND_DATETIME));
        writer.add(factory.createEndElement("", "", BatchConstants.HEADER));
    } catch (XMLStreamException e) {
        this.logger.logError(e.getMessage(), e);
    }

我可以使用此内容覆盖上述代码段的测试

    @Test
    public void testWrite() throws IOException, XMLStreamException {

    BatchProcessControlEntity batchProcessControlEntity = new BatchProcessControlEntity();
    batchProcessControlEntity.setCreatedDt(new Date());
    Mockito.when(this.batchProcessControlJpaRepository.findByBatchProcessCtrlId(Matchers.anyObject()))
        .thenReturn(batchProcessControlEntity);

    XMLEventWriter eventWriter = Mockito.mock(XMLEventWriter.class);

    this.headerWriter.write(eventWriter);
}

但是我不知道触发XMLStreamException需要什么输入。谢谢你。

Answer 1

您使用了模仿的doThrow方法。

不错的tutorial here
doThrow javaDoc here

一些有趣的示例代码：

XMLEventWriter eventWriter = Mockito.mock(XMLEventWriter.class);
doThrow(new XMLStreamException("This is my exception"))
        .when(eventWriter)
        .add(any(XMLEvent.class));

如何在测试类中触发XMLStreamException

1 个答案: