Question

我有一个python脚本，该脚本使用 Configparser 模块获取连接参数。

当我通过cmd提示符调用此脚本时，它可以按预期工作：

C:\Users\vino>C:\Python37-32\python.exe C:\Python37-32\dim.py

我计划通过VBA做到这一点：

因此，我创建了以下Excel宏（2010 Excel）：

Public Sub StartExeWithArgument()
  Dim strProgramName As String
  Dim strArgument As String
  strpythonpath = "C:\Python37-32\python.exe"
  strProgramName = "C:\Python37-32\dim.py"

  Call Shell("""" & strpythonpath & """ """ & strProgramName & """", vbNormalFocus)
End Sub

但是上面的代码抛出错误：

Traceback (most recent call last):
  File "dim.py", line 16 in <module>
  File "configparser.py", line 958, in __getitem__
KeyError: 'SIT'
[8700] Failed to execute script dim

configparser的输入文件：

[SIT]
address=localhost
port=9049
user=vino
password=apple
ssl=False

Python代码：

import configparser
import os
import sys
cube_name = 'Sales'
config = configparser.ConfigParser()
from pathlib import Path
cwd = Path().absolute()
config.read(os.path.join(cwd, 'config.ini'))
metadata_file = os.path.join(cwd, cube_name+'.xlsx')

import pandas as pd
from TM1py.Services import TM1Service
from TM1py.Utils import Utils

# Connection to TM1. Needs Address, Port, Credentials, and SSL
with TM1Service(**config['SIT']) as tm1:
    all_cubes = tm1.cubes.get(cube_name)
    dims = all_cubes.dimensions
    with pd.ExcelWriter(metadata_file) as writer:
        for dim in dims:
            df = []
            dimension = tm1.dimensions.get(dim)
            for hierarchy in dimension:
                for element in hierarchy:
                    df.append(element.name)
                pd.DataFrame(df).to_excel(writer, sheet_name=dim, header=False, index=False)

使用VBA Shell运行python脚本时出现问题

0 个答案: