Question

假设我有一个这样的收藏集：

{ "_id" : 8751, "title" : "The Banquet", "author" : "Dante" }
{ "_id" : 8752, "title" : "Divine Comedy", "author" : "Dante", "copies" : 1 }
{ "_id" : 8645, "title" : "Eclogues", "author" : "Dante" }
{ "_id" : 7000, "title" : "The Odyssey", "author" : "Homer", "copies" : 10 }
{ "_id" : 7020, "title" : "Iliad", "author" : "Homer", "copies" : 10 }

我如何仅使用具有“副本”字段的文档来生成新集合，以获得这样的新集合：

{ "_id" : 8752, "title" : "Divine Comedy", "author" : "Dante", "copies" : 1 }
{ "_id" : 7000, "title" : "The Odyssey", "author" : "Homer", "copies" : 10 }
{ "_id" : 7020, "title" : "Iliad", "author" : "Homer", "copies" : 10 }

Answer 1

您可以使用$out运算符根据汇总结果创建新集合，请尝试：

pipeline = [
    { $match: { copies: { $exists: true } } }
    { $out: "newCollectionName" }
]

db.collection.aggregate(pipeline)

从mongodb中的其他集合创建新集合

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