无法在Zkill脚本中查明我的错误

Question

我正在尝试在cron中创建一个脚本来杀死僵尸进程。我需要它每小时运行一次，并在检测到僵尸时显示日志消息。我创建了一个bash脚本，但收到许多错误，包括意外的文件结尾。

我尝试创建cron作业，但是不确定该过程以及如何设置它。

#!/bin/bash
case "$1" in
--admin)
        stat=`ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print"pid: "$3" *** parent_pid: "$4" *** status: "$10" *** process: "$13}' | grep ": Z"`

        if ((${#stat} > 0));then
            echo zombie processes found:
        echo .
        ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print"pid: "$3" *** parent_pid: "$4" *** status: "$10" *** process: "$13}' | grep ": Z"
        echo -n "Kill zombies? [y/n]: "
        read keyb
        if [ $keyb == 'y' ];then
        echo killing zombies..
        ps ax | awk '{print $1}' | grep -v "PID" | xargs -n 1 ps lOp | grep -v "UID" | awk '{print$4" status:"$10}' | grep "status:Z" | awk '{print $1}' | xargs -n 1 kill -9
        fi
    else
        echo no zombies found!
    fi
;;