我有一个脚本,可以将收到的电子邮件发送到我的gmail,但现在我也想获取通过电子邮件发送的电子邮件。
这是我要收到传入电子邮件的代码
请让我知道我也需要外发电子邮件
此代码目前通过console.google.com上的pub sub运行
$ch = curl_init('https://www.googleapis.com/gmail/v1/users/me/messages?labelIds=Label_56&maxResults=10');
curl_setopt_array($ch, array(
CURLOPT_POST => false,
CURLOPT_RETURNTRANSFER => TRUE,
CURLOPT_HTTPHEADER => array(
'Authorization: Bearer '. $tokenval,
'Content-Type: application/json',
),
));
// execute request and get response
$result = curl_exec($ch);
$allmessages = json_decode($result);
$allmessage = $allmessages->messages;
for($i=0;$i<count( $allmessage);$i++)
{
//echo $allmessage[$i]->id;
$checkoldmsgid = $this->Customer_m->getCount('messages',array('massageid'=>$allmessage[$i]->id ));
if( $checkoldmsgid ==0)
{
$ch = curl_init('https://www.googleapis.com/gmail/v1/users/me/messages/'.$allmessage[$i]->id);
curl_setopt_array($ch, array(
CURLOPT_POST => false,
CURLOPT_RETURNTRANSFER => TRUE,
CURLOPT_HTTPHEADER => array(
'Authorization: Bearer '. $tokenval,
'Content-Type: application/json'
),
));
// execute request and get response
$resultm = curl_exec($ch);
$msgval = json_decode($resultm);
$sendernum =explode('@',$msgval->payload->headers[19]->value);
$recivernum =explode('@',$msgval->payload->headers[0]->value);
$createdat = date('Y-m-d H:i:s',strtotime($msgval->payload->headers[18]->value));
$massage = $msgval->snippet;
$single_message = $service->users_messages->get("me", $allmessage[$i]->id);
$payload = $single_message->getPayload();
$body = $payload->getBody();
$FOUND_BODY = $this->decodeBody($body['data']);
答案 0 :(得分:0)
您可能会在SENT
通话中使用Label_56
system label(而不是curl_init()
)
已发送
自动应用于以drafts.send发送的邮件 或messages.send,并插入messages.insert和 用户在发件人标头中发送的电子邮件,或由用户通过 Web界面。