Question

我正在渲染如下所示的JSON日期：import functools from Crypto.PublicKey import RSA from Crypto.Cipher import PKCS1_OAEP if __name__ == '__main__': # Encrypt with open('public.pem', 'r') as fp: pub = fp.read() fp.close() public = RSA.importKey(pub) # tockage du fichier dans une variable rep with open('test.csv', 'r') as fichier: rep = fichier.read() # liminations des spaces rep = rep.replace(' ', '') # ncodage pour type bytes rep = rep.encode() cipher = PKCS1_OAEP.new(public) # decoupage en mot de 10 chars rep = [rep[i:i+10] for i in range(0, len(rep), 10)] # Open the file in binary mode so we can write bytes. with open('encrypted.csv', 'wb') as fichier2: for i in rep: fichier2.write(cipher.encrypt(i)) # Decrypt with open('private.pem', 'r') as fk: priv = fk.read() private = RSA.importKey(priv) CHUNK_SIZE = 256 # Open the file in binary mode so we can read bytes. with open('encrypted.csv', 'rb') as fichier: # Create an iterator that will return chunks of the correct size. chunker = iter(functools.partial(fichier.read, CHUNK_SIZE), b'') rep = list(chunker) cipher = PKCS1_OAEP.new(private) with open('decrypted.csv', 'w') as fichier2: for i in rep: decrypted_line = cipher.decrypt(i) fichier2.write(decrypted_line.decode())，并且试图将其转换为/Date(1185336000000)/类型的格式。

我尝试了一种("mmmm d, yyyy")和一种if...includes()方法，但是它们不起作用（语法错误），并且禁用了已渲染的数据。

JS代码段：

format()

JSON代码段：

import firmData from '../JSON/firmDir.json';

function loadBio() {

let dateOfHire = firmData.d.results.map(function(val) {
      // if (val.hiredate === null || undefined) return " ";
      let newDate = val.hiredate;
      if (newDate.includes('000')) {
           newDate.format("mmmm d, yyyy");
      }
    return val.hiredate
 })

$("#hireDate-id").append(dateOfHire);

}

loadBio()

Answer 1

嘿，我刚刚创建了此功能-也许这对解决您的问题有帮助吗？

const date = "/Date(1185336000000)/";
function format(date:string) {
    const matches = date.match(/\d+/);
    const ts = matches[0]; 
    const dateObj = new Date(ts*1);
    const day = dateObj.getDay();
    const month = dateObj.getMonth();
    const year = dateObj.getFullYear();

    return day, month, year; // returns 3 6 2007
}

转换JSON日期

JS代码段：

JSON代码段：

1 个答案: