Question

如何将从迭代行中提取的子字符串连接成一个字符串？非常感谢您的帮助。

假设我有文件text.txt

One is 1
Two is 2
Three is 3

我想从该文件中提取单个字符串“ 1、2、3” 我可能错误地尝试了line.replace（）和rstrip（），但两者均未提供所需的输出。我的代码如下所示。

def getnum():
    with open("text.txt", "r") as f:
        for line in f:
            line.replace("\n", ",")
            col=line.split(" is ")
            num=col[0]
            print(num)
    f.close()
    return

def getnum2():
    with open("text.txt", "r") as f:
        for line in f:
            col=line.split(" is ")
            num=col[0] + ","
            num.rstrip("\n")
            print(num)
    f.close()
    return


if __name__ == "__main__":
    #getnum()
    getnum2()

尝试第一个功能时得到的实际结果是

One
Two
Three

尝试第二个功能时得到的实际结果是

One,
Two,
Three,

Answer 1

如果文件大小不大，并且您想将所需的单词存储在列表中，则可以将它们加入为：

def getnum():
    with open("text.txt", "r") as f:
        word_list = []
        for line in f:
            col = line.split(" is ")
            word_list.append(col[0])
        print((", ").join(word_list))

或者您可以使用以下方法在读取文件时进行打印：

对于python2：

def getnum():
    with open("text.txt", "r") as f:
        flag = False
        for line in f:
            if flag:
                print ",",
            flag = True
            col=line.split(" is ")
            num=col[0]
            print num,
    f.close()
    return

对于python3：

def getnum():
    with open("text.txt", "r") as f:
        flag = False
        for line in f:
            if flag:
                print (",", end=" ")
            flag = True
            col=line.split(" is ")
            num=col[0]
            print (num, end="")
    f.close()
    return

如何将文件中各行的迭代合并为一个字符串？

1 个答案: