据我了解,Doctrine需要多对一关联,以便在一侧引用主键。 (请参见here或here)
如何解决在教义2中由唯一键引用的多对一关联?
在下面的内容中,我将展示到目前为止所提出的内容并遇到上述问题。要使其在我的上下文中起作用,必须进行哪些更改?
就我而言:
除其他属性外,项目还具有snapshotId
和cid
。 cid
代表内部项目编号。在某些更改下,将拍摄快照并将其保留为唯一的snapshotId
(包括关联表中的所有相关条目-此处未显示)。快照ID为空(空)的条目是当前状态。
正在ProjectHistory
中跟踪项目的更改。出于演示目的,该实体具有属性function
,modifyDate
和modifyUserId
。
该项目与ProjectHistory具有一对多关联。 ProjectHistory与Project的多对一关联。前者按预期工作,后者带来了开头提到的错误。
<?php
namespace App\Entity;
use Doctrine\Common\Collections\ArrayCollection;
use Doctrine\Common\Collections\Collection;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity()
* @ORM\Table(
* indexes={
* @ORM\Index(
* name="cid",
* columns={"cid"}
* ),
* },
* uniqueConstraints={
* @ORM\UniqueConstraint(
* name="unique_snapshot_per_project",
* columns={"snapshot_id", "cid"}
* ),
* },
* )
*/
class Project
{
/**
* @ORM\Id()
* @ORM\Column(type="guid")
* @ORM\GeneratedValue(strategy="UUID")
* @var string
*/
private $id;
/**
* @ORM\Column(type="guid", unique=true, nullable=true)
* @var string|null
*/
private $snapshotId;
/**
* @ORM\Column()
* @var string
*/
private $cid;
/**
* @ORM\OneToMany(targetEntity="ProjectHistory", mappedBy="projectCid", cascade={"persist"})
* @var Collection|ProjectHistory[]
*/
private $projectHistories;
public function __construct()
{
$this->projectHistories = new ArrayCollection();
}
public function toArray(): array
{
return [
'id' => $this->getId(),
'snapshotId' => $this->getSnapshotId(),
'cid' => $this->getCid(),
'projectHistories' => $this->getProjectHistoriesAsArray(),
];
}
public function getProjectHistoriesAsArray(): array
{
$projectHistories = [];
foreach ($this->getProjectHistories() as $projectHistory) {
$projectHistories[] = $projectHistory->toArray();
}
return $projectHistories;
}
public function getId(): ?string
{
return $this->id;
}
public function setId(string $id): void
{
$this->id = $id;
}
public function getSnapshotId(): ?string
{
return $this->snapshotId;
}
public function setSnapshotId(string $snapshotId): void
{
$this->snapshotId = $snapshotId;
}
public function getCid(): string
{
return $this->cid;
}
public function setCid(string $cid): void
{
$this->cid = $cid;
}
public function getProjectHistories(): Collection
{
return $this->projectHistories;
}
/**
* @param ArrayCollection|ProjectHistory[] $projectHistories
* @return Project
*/
public function addProjectHistories(ArrayCollection $projectHistories): Project
{
foreach ($projectHistories as $projectHistory) {
if (! $this->projectHistories->contains($projectHistory)) {
$this->projectHistories->add($projectHistory);
$projectHistory->setProject($this);
}
}
return $this;
}
/**
* @param ArrayCollection|ProjectHistory[] $projectHistories
* @return Project
*/
public function removeProjectHistories(ArrayCollection $projectHistories): Project
{
foreach ($projectHistories as $projectHistory) {
if ($this->projectHistories->contains($projectHistory)) {
$this->projectHistories->remove($projectHistory);
}
}
return $this;
}
}
<?php
namespace App\Entity;
use DateTime;
use DateTimeInterface;
use Doctrine\ORM\Mapping as ORM;
/**
* @ORM\Entity()
*/
class ProjectHistory
{
/**
* @ORM\Id()
* @ORM\Column(type="guid")
* @ORM\GeneratedValue(strategy="UUID")
* @var string
*/
private $id;
/**
* @ORM\Column()
* @var string
*/
private $function;
/**
* @ORM\Column(type="datetime")
* @var Datetime
*/
private $modifyDate;
/**
* @ORM\Column(type="guid")
* @var string
*/
private $modifyUserId;
/**
* @ORM\ManyToOne(targetEntity="Project", inversedBy="projectHistories")
* @ORM\JoinColumn(name="project_cid", referencedColumnName="cid")
* @var Project
*/
private $project;
public function toArray(): array
{
return [
'id' => $this->getId(),
'projectCid' => $this->getProjectCid(),
'function' => $this->getFunction(),
'modifyDate' => $this->getModifyDateAsString(),
'modifyUserId' => $this->getModifyUserId(),
];
}
public function getModifyDateAsString(): string
{
if (null === $this->getModifyDate()) {
return '';
}
return $this->getModifyDate()->format(DateTimeInterface::ATOM);
}
public function getProjectCid(): ?string
{
if (null !== $this->getProject()) {
return $this->getProject()->getCid();
}
return null;
}
public function getId(): ?string
{
return $this->id;
}
public function setId(string $id): void
{
$this->id = $id;
}
public function getFunction(): string
{
return $this->function;
}
public function setFunction($function): void
{
$this->function = $function;
}
public function getModifyDate(): DateTime
{
return $this->modifyDate;
}
public function setModifyDate(DateTime $modifyDate): void
{
$this->modifyDate = $modifyDate;
}
public function getModifyUserId(): string
{
return $this->modifyUserId;
}
public function setModifyUserId(string $modifyUserId): void
{
$this->modifyUserId = $modifyUserId;
}
public function getProject(): ?Project
{
return $this->project;
}
public function setProject(Project $project): void
{
$this->project = $project;
}
}
任何帮助将不胜感激。让我知道,如果您需要更多信息。
答案 0 :(得分:1)
通常,如果您需要进行此类操作,我的意思是使用非主键进行引用,则说明您的设计存在问题。阅读问题时,我想到的第一件事是Event Soursing。 ES for PHP很好地体现了-prooph。不幸的是,将现有项目重构为ES并非易事,但也许可以帮助您更好地理解历史更改和快照的概念。
根据当前情况,我可以说Project
并不是快照。您可以修改模型并创建与ProjectSnapshot
相关的Project
实体,然后ProjectHistory
将与ProjectSnapshot
相关。另外,我不建议您在快照中存储任何关联(和外键),而只保存相关实体的标识符。请注意loggable extension,可能会有用。