我正在写Firebase实时数据库。如何正确写入数据库?
没有发现错误。但是我将将实时数据库添加到应用程序的依赖性从com.google.firebase:firebase-database:16.0.1
更改为com.google.firebase:firebase-database:16.0.6
。
这是定义的变量
private DatabaseReference mDatabase;
这是我的注册活动代码部分
private void register_user (final String displayName, String email, String password){
mAuth.createUserWithEmailAndPassword(email, password).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
if (task.isSuccessful()) {
FirebaseUser current_user = FirebaseAuth.getInstance().getCurrentUser();
String uid = current_user.getUid();
mDatabase = FirebaseDatabase.getInstance().getReference().child("Users").child(uid);
HashMap<String,String> userMap = new HashMap<>();
userMap.put("name",displayName);
userMap.put("status","Hey there I am using ChatApp");
userMap.put("image","default");
userMap.put("thumb_image","default");
mDatabase.setValue(userMap);
} else {
mRegProgress.hide();
Toast.makeText(RegisterActivity.this, "Couldn't Sign in.Please Check and Try Again", Toast.LENGTH_LONG).show();
}
}
});
}
数据条目应存储在数据库中
答案 0 :(得分:0)
Firebase Realtime Database的默认安全规则拒绝读取和写入。因此,您需要在Firebase控制台中检查和更改安全规则。
将安全规则更改为
{
"rules": {
"Users": {
"$uid": {
".read": "$uid === auth.uid",
".write": "$uid === auth.uid"
}
}
}
}
有关更多安全选项,请查看firebase docs