Question

我在mysql的video_status_ids中有一些json数据，我正在尝试检索所有具有3个记录的

    long downloadReference = 0;

    downloadManager = (DownloadManager)getSystemService(DOWNLOAD_SERVICE);
    try {
        DownloadManager.Request request = new DownloadManager.Request(uri);

        //Setting title of request
        request.setTitle(fileName);

        //Setting description of request
        request.setDescription(getString(R.string.downloadingnow));

        //set notification when download completed
        request.setNotificationVisibility(DownloadManager.Request.VISIBILITY_VISIBLE_NOTIFY_COMPLETED);

        //Set the local destination for the downloaded file to a path within the application's external files directory
        request.setDestinationInExternalPublicDir(fileStorageDestinationUri, fileName);

        request.allowScanningByMediaScanner();

        //Enqueue download and save the referenceId
        downloadReference = downloadManager.enqueue(request);
    } catch (IllegalArgumentException e) {
       this.showToast(getString(R.string.downloadnotavilablenow));


    }
    return downloadReference;
}

演示记录

MySql version: 5.7.23

查询

[3, 6, 9]

[7, 3, 10]

结果0条记录

Answer 1

您最好使用JSON_CONTAINS

SQL > select * from zz where json_contains(doc,'3');
+-----+------------+
| _id | doc        |
+-----+------------+
|   1 | [3, 6, 9]  |
|   2 | [7, 3, 10] |
+-----+------------+
2 rows in set (0.0007 sec)

并确保它对我们没有的值正确起作用

SQL > select * from zz where json_contains(doc,'2');
Empty set (0.0006 sec)

使用JSON_SEARCH匹配JSON数据中的整数

1 个答案: