我试图将Jcombobox值插入我的sqlite数据库中,但是每当我运行该程序时,它只会在我的数据库中插入“ 9”。请指教。我正在尝试将用户选择的整数导入我的sqlite数据库。由于某些原因,即使使用动作侦听器,仍将默认值9输入到表中,但不确定为什么。这是完整的代码,不包括连接和Jtable。
public class create extends JFrame {
private JPanel contentPane;
private JTextField textField;
private JTextField textField_1;
/**
* Launch the application.
*/
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
public void run() {
try {
create frame = new create();
frame.setVisible(true);
} catch (Exception e) {
e.printStackTrace();
}
}
});
}
Connection connect = null;
private JTextField textField_2;
String uniqueString = UUID.randomUUID().toString();
private JTextField textField_3;
/**
* Create the frame.
*/
public create() {
connect = connection.dbConnector();
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setBounds(100, 100, 450, 300);
contentPane = new JPanel();
contentPane.setBackground(new Color(204, 204, 204));
contentPane.setBorder(new EmptyBorder(5, 5, 5, 5));
setContentPane(contentPane);
contentPane.setLayout(null);
JLabel lblStudentName = new JLabel("Student ID:");
lblStudentName.setBounds(96, 69, 72, 16);
contentPane.add(lblStudentName);
textField = new JTextField();
textField.setBounds(173, 64, 216, 26);
contentPane.add(textField);
textField.setColumns(10);
JLabel lblGrade = new JLabel("Grade:");
lblGrade.setBounds(125, 107, 47, 16);
contentPane.add(lblGrade);
JComboBox comboBox = new JComboBox();
comboBox.addItem(9);
comboBox.addItem(10);
comboBox.addItem(11);
comboBox.addItem(12);
comboBox.setBounds(173, 102, 72, 29);
contentPane.add(comboBox);
comboBox.setSelectedItem(9);
comboBox.addActionListener(comboBox);
int selectedNumber = (int)comboBox.getSelectedItem();
JLabel lblInputBookOver = new JLabel("Teacher:");
lblInputBookOver.setBounds(111, 146, 61, 21);
contentPane.add(lblInputBookOver);
textField_1 = new JTextField();
textField_1.setBounds(173, 143, 216, 26);
contentPane.add(textField_1);
textField_1.setColumns(10);
JButton button = new JButton("<");
button.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
for (int count = 0; count <= 0; count++) {
//dispose();
options sc = new options();
sc.setVisible(true);
}
}
});
button.setBounds(6, 6, 30, 29);
contentPane.add(button);
JLabel lblStudentname = new JLabel("Student Name:");
lblStudentname.setBounds(74, 31, 99, 16);
contentPane.add(lblStudentname);
textField_2 = new JTextField();
textField_2.setBounds(173, 26, 216, 26);
contentPane.add(textField_2);
textField_2.setColumns(10);
JLabel lblEmail = new JLabel("Email:");
lblEmail.setBounds(125, 180, 42, 26);
contentPane.add(lblEmail);
textField_3 = new JTextField();
textField_3.setBounds(173, 180, 216, 26);
contentPane.add(textField_3);
textField_3.setColumns(10);
JButton btnCheckout = new JButton("Checkout");
btnCheckout.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
final String uniqueString = UUID.randomUUID().toString().replace("-", "");
try {
String query = "insert into data ('Name', 'Student ID', 'Teacher', 'Grade', 'Email', 'Ebook') values (?,?,?,?,?,?)";
PreparedStatement pst = connect.prepareStatement(query);
pst.setString(1,textField_2.getText() );
pst.setString(2,textField.getText() );
pst.setString(3,textField_1.getText() );
pst.setInt(4, selectedNumber);
pst.setString(5,textField_3.getText() );
pst.setString(6, uniqueString);
for (int count = 0; count <= 0; count++) {
//dispose();
confirm sc = new confirm();
sc.setVisible(true);
count = 0;
}
pst.execute();
pst.close();
}
catch (Exception w){
w.printStackTrace();
}
}
});
btnCheckout.setBounds(173, 218, 117, 29);
contentPane.add(btnCheckout);
}
}
答案 0 :(得分:0)
由于所选项目始终为9,因此它将9插入数据库中,这是因为您首先将其添加到了组合框中。为了插入选定的值,您将必须使用ActionListener.,然后才能进行用户的选择并做任何您想做的事情。
其用法示例:
if (!ctx._source.user_ids.contains(users)){ctx._source.user_ids += users}