Question

我在jquery中有一个JSON对象，如下所示：-

promotions

我必须将带有multipart / form-data的POST请求发送到服务器。我创建了一个FormData对象：-

category

我需要做的是遍历JSON中的每个元素，并将它们附加到我的变量fd中。这就是我想要的：-

id

有什么想法要实现吗？

Answer 1

您可以使用for

迭代对象

for (var key in userObj) {
  fd.append(key, userObj[key]);
}

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for...in

Answer 2

您可以这样做：

let userObj = { 
 "loginId":"abc123", 
 "class":"5", 
 "email":"akhil.gts1997@gmail.com", 
 "level":"1"
};

let fd = new FormData();

for (let key in userObj){
    fd.append(key, userObj[key])
}

Answer 3

git commit

Answer 4

var userObj =
{ 
 "loginId":"abc123", 
 "class":"5", 
 "email":"akhil.gts1997@gmail.com", 
 "level":"1"
}
var fd = new FormData(); 
$.each(userObj, function(i, val) {
  console.log(i + " " + val);
  fd.append(i, val);
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.0.0/jquery.min.js"></script>

Try something like this.

Answer 5

let userObj = { 
 "loginId":"abc123", 
 "class":"5", 
 "email":"akhil.gts1997@gmail.com", 
 "level":"1"
};

var newdata= new FormData();

 $.each(userObj, function (key, value) {
    newdata.append(key, userObj[key]);
    console.log(key, userObj[key])
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

遍历JSON对象以在jQuery中向FormData添加值

5 个答案: